Epson S1C63000 manual 57

CHAPTER 4: INSTRUCTION SET

	Mnemonic					Machine code										Operation	Cycle		Flag			EXT.	Page
		12	11	10	9		8	7	6	5	4	3	2	1	0			E	I	C	Z	mode
INC	[%X],n4	1	1	1	0	1		1	0	0	0	[ 10H-n4 ]				[X] ← N's adjust ([X]+1)	2	↓	–↔ ↔			●	93
	[%X]+,n4	1	1	1	0	1		1	0	0	1	[ 10H-n4 ]				[X] ← N's adjust ([X]+1), X← X+1	2	↓	–↔ ↔			⋅	93
	[%Y],n4	1	1	1	0	1		1	0	1	0	[ 10H-n4 ]				[Y] ← N's adjust ([Y]+1)	2	↓	–↔ ↔			●	93
	[%Y]+,n4	1	1	1	0	1		1	0	1	1	[ 10H-n4 ]				[Y] ← N's adjust ([Y]+1), Y← Y+1	2	↓	–↔ ↔			⋅	93
	[00addr6]	1	0	0	0	0		0	1 a5 a4			a3 a2 a1 a0				[00addr6] ← [00addr6]+1	2	↓	–↔ ↔			⋅	92
INT	imm6	1	1	1	1	1		1	0	i5 i4		i3 i2 i1 i0				[SP2-1] ← F, SP2 ← SP2-1	3	↓ –		–	–	⋅	94
																([(SP1-1)∗4+3]~[(SP1-1)∗4]) ← PC+1,
																SP1 ← SP1-1, PC ← imm6 (imm6=0100H~013FH)
JP	%Y	1	1 1 1 1					1 1 1 1				0 0 1 X				PC ← Y	1	↓ – – –				⋅	95
JR	%A	1	1	1	1	1		1	1	1	1	0	0	0	1	PC ← PC+A+1	1	↓ – – –				⋅	95
	%BA	1	1	1	1	1		1	1	1	1	0	0	0	0	PC ← PC+BA+1	1	↓ – – –				⋅	96
	sign8	0	0	0	0	0		s7 s6 s5 s4				s3 s2 s1 s0				PC ← PC+sign8+1 (sign8=-128~127)	1	↓ –		–	–	●	97
	[00addr6]	1	1	1	1	1		0	1 a5 a4			a3 a2 a1 a0				PC ← PC+[00addr6]+1	2	↓ –		–	–	⋅	96
JRC	sign8	0	0	1	0	0		s7 s6 s5 s4				s3 s2 s1 s0				If C=1 then PC ← PC+sign8+1 (sign8=-128~127)	1	↓ –		–	–	●	97
JRNC	sign8	0	0	1	0	1		s7 s6 s5 s4				s3 s2 s1 s0				If C=0 then PC ← PC+sign8+1 (sign8=-128~127)	1	↓ –		–	–	●	98
JRNZ	sign8	0	0	1	1	1		s7 s6 s5 s4				s3 s2 s1 s0				If Z=0 then PC ← PC+sign8+1 (sign8=-128~127)	1	↓ –		–	–	●	98
JRZ	sign8	0	0	1	1	0		s7 s6 s5 s4				s3 s2 s1 s0				If Z=1 then PC ← PC+sign8+1 (sign8=-128~127)	1	↓ –		–	–	●	99
LD	%A,%A	1	1	1	1	0		1	1	1	1	0	0	0	0	A ← A	1	↓ – – –				⋅	99
	%A,%B	1	1	1	1	0		1	1	1	1	0	0	1	0	A ← B	1	↓ – – –				⋅	99
	%A,%F	1	1	1	1	1		1	1	1	1	0	1	1	0	A ← F	1	↓ – – –				⋅	99
	%A,imm4	1	1	1	1	0		1	1	0	0	i3 i2 i1 i0				A ← imm4	1	↓ – – –				⋅	100
	%A,[%X]	1	1	1	1	0		1	1	1	0	0	0	0	0	A ← [X]	1	↓ – – –				●	100
	%A,[%X]+	1	1	1	1	0		1	1	1	0	0	0	0	1	A ← [X], X ← X+1	1	↓ – – –				⋅	101
	%A,[%Y]	1	1	1	1	0		1	1	1	0	0	0	1	0	A ← [Y]	1	↓ – – –				●	100
	%A,[%Y]+	1	1	1	1	0		1	1	1	0	0	0	1	1	A ← [Y], Y ← Y+1	1	↓ – – –				⋅	101
	%B,%A	1	1	1	1	0		1	1	1	1	0	1	0	0	B ← A	1	↓ – – –				⋅	99
	%B,%B	1	1	1	1	0		1	1	1	1	0	1	1	0	B ← B	1	↓ – – –				⋅	99
	%B,imm4	1	1	1	1	0		1	1	0	1	i3 i2 i1 i0				B ← imm4	1	↓ – – –				⋅	100
	%B,[%X]	1	1	1	1	0		1	1	1	0	0	1	0	0	B ← [X]	1	↓ – – –				●	100
	%B,[%X]+	1	1	1	1	0		1	1	1	0	0	1	0	1	B ← [X], X ← X+1	1	↓ – – –				⋅	101
	%B,[%Y]	1	1	1	1	0		1	1	1	0	0	1	1	0	B ← [Y]	1	↓ – – –				●	100
	%B,[%Y]+	1	1	1	1	0		1	1	1	0	0	1	1	1	B ← [Y], Y ← Y+1	1	↓ – – –				⋅	101
	%F,%A	1	1	1	1	1		1	1	1	1	0	1	0	1	F ← A	1	↔ ↔ ↔ ↔				⋅	99
	%F,imm4	1	0	0	0	0		1	0	1	1	i3 i2 i1 i0				F ← imm4	1	↔ ↔ ↔ ↔				⋅	100
	[%X],%A	1	1	1	1	0		1	1	1	0	1	0	0	0	[X] ← A	1	↓ – – –				●	101
	[%X],%B	1	1	1	1	0		1	1	1	0	1	1	0	0	[X] ← B	1	↓ – – –				●	101
	[%X],imm4	1	1	1	1	0		1	0	0	0	i3 i2 i1 i0				[X] ← imm4	1	↓ –		–	–	●	102
	[%X],[%Y]	1	1	1	1	0		1	1	1	1	1	0	1	0	[X] ← [Y]	2	↓ –		–	–	⋅	103
	[%X],[%Y]+	1	1	1	1	0		1	1	1	1	1	0	1	1	[X] ← [Y], Y ← Y+1	2	↓ –		–	–	⋅	104
	[%X]+,%A	1	1	1	1	0		1	1	1	0	1	0	0	1	[X] ← A, X ← X+1	1	↓ – – –				⋅	102
	[%X]+,%B	1	1	1	1	0		1	1	1	0	1	1	0	1	[X] ← B, X ← X+1	1	↓ – – –				⋅	102
	[%X]+,imm4	1	1	1	1	0		1	0	0	1	i3 i2 i1 i0				[X] ← imm4, X ← X+1	1	↓ –		–	–	⋅	103
	[%X]+,[%Y]	1	1	1	1	0		1	1	1	1	1	1	1	0	[X] ← [Y], X ← X+1	2	↓ –		–	–	⋅	104
	[%X]+,[%Y]+	1	1	1	1	0		1	1	1	1	1	1	1	1	[X] ← [Y], X ← X+1, Y ← Y+1	2	↓ –		–	–	⋅	105
	[%Y],%A	1	1	1	1	0		1	1	1	0	1	0	1	0	[Y] ← A	1	↓ – – –				●	101
	[%Y],%B	1	1	1	1	0		1	1	1	0	1	1	1	0	[Y] ← B	1	↓ – – –				●	101
	[%Y],imm4	1	1	1	1	0		1	0	1	0	i3 i2 i1 i0				[Y] ← imm4	1	↓ –		–	–	●	102
	[%Y],[%X]	1	1	1	1	0		1	1	1	1	1	0	0	0	[Y] ← [X]	2	↓ –		–	–	⋅	103
	[%Y],[%X]+	1	1	1	1	0		1	1	1	1	1	0	0	1	[Y] ← [X], X ← X+1	2	↓ –		–	–	⋅	104
	[%Y]+,%A	1	1	1	1	0		1	1	1	0	1	0	1	1	[Y] ← A, Y ← Y+1	1	↓ – – –				⋅	102
	[%Y]+,%B	1	1	1	1	0		1	1	1	0	1	1	1	1	[Y] ← B, Y ← Y+1	1	↓ – – –				⋅	102
	[%Y]+,imm4	1	1	1	1	0		1	0	1	1	i3 i2 i1 i0				[Y] ← imm4, Y ← Y+1	1	↓ –		–	–	⋅	103
	[%Y]+,[%X]	1	1	1	1	0		1	1	1	1	1	1	0	0	[Y] ← [X], Y ← Y+1	2	↓ –		–	–	⋅	104
	[%Y]+,[%X]+	1	1	1	1	0		1	1	1	1	1	1	0	1	[Y] ← [X], Y ← Y+1, X ← X+1	2	↓ –		–	–	⋅	105
LDB	%BA,%EXT	1	1	1	1	1		1	1	0	1	0	1	1	X	BA ← EXT	1	↓ – – –				⋅	106
	%BA,%SP1	1	1	1	1	1		1	1	0	0	1	1	0	X	BA ← SP1	1	↓ – – –				⋅	107
	%BA,%SP2	1	1	1	1	1		1	1	0	0	1	1	1	X	BA ← SP2	1	↓ – – –				⋅	107
	%BA,%XH	1	1	1	1	1		1	1	0	0	1	0	0	1	BA ← XH	1	↓ – – –				⋅	107
	%BA,%XL	1	1	1	1	1		1	1	0	0	1	0	0	0	BA ← XL	1	↓ – – –				⋅	107

S1C63000 CORE CPU MANUAL EPSON 51