4 VctA • VctB (Vector dot product)

AVctA15(VECTOR)7(Dot)VctB=

VCT

5 VctA ⋅ VctB (Vector cross product)

AVctA*VctB=

VCT

6 Obtain the absolute values of VctC.

A1w(Abs)VctC)=

VCT

7 Determine the angle formed by VctA and VctB to three decimal places (Fix 3). v

 

•

B)

 

•

B)

 

(cos  =

(A

, which becomes  = cos–1

(A

)

AB

 

 

 

 

AB

1N(SETUP)6(Fix)3

A(VctA15(VECTOR)7(Dot)VctB)/

VCT FIX

(1w(Abs)VctA)1w(Abs) VctB))=

VCT FIX

1c(cos–1)G)=

InequalityCalculations(INEQ)

You can use the following procedure to solve a quadratic inequality or cubic inequality.

1. Press Nc1(INEQ) to enter the INEQ Mode.

2. On the menu that appears, select an inequality type.

To select this inequality type:

Press this key:

 

 

 

Quadratic inequality

1(aX2

+ bX + c )

Cubic inequality

2(aX3

+ bX2 + cX + d )

3. On the menu that appears, use keys 1through 4to select the inequality symbol type and orientation.

4. Use the Coefficient Editor that appears to input coefficient values.

• To solve x2 + 2x – 3 < 0, for example, input the coefficients a = 1, b = 2, c = –3 by pressing 1=2 =-3 =.

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