Trane TRG-TRC013-EN manual 3,500 cfm ⋅ 2.0 in. H2O, = 55%, 1.65 m3/s ⋅ 491 Pa, ⋅ 1.5 kW

g

Static Efficiency

SE	3,500 cfm ⋅ 2.0 in. H2O			= 55%
	=	6,362 ⋅ 2.0 hp
SE	=	1.65 m3/s ⋅ 491 Pa		= 55%
			⋅ 1.5 kW
	982

g FF

Let’s assume that the fan from the previous example, delivering 3,500 cfm [1.65 m9/s] at 2.0 in. H8O [491 Pa] of static pressure, requires 2.0 hp [1.5 kW] of input power. At these conditions, the fan’s static efficiency would be:

Static Efficiency (%)	=	3,500 cfm ⋅ 2.0 in. H8O
		-------------6,362-----------------⋅-----2.0----------hp------------------			= 55%
Static Efficiency (%)	=	1.65 m9	/s ⋅ 491 Pa	=	55%
		---------982-----------⋅-----1.5----------kW----------------

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