AIR FOR COMBUSTION
AND VENTILATION
Continued
Unusually tight construction is defined as con- struction where:
a.walls and ceilings exposed to the outside atmosphere have a continuous water vapor retarder with a rating of one perm (6 x 10- 11 kg per
b.weather stripping has been added on open- able windows and doors and
c.caulking or sealants are applied to areas such as joints around window and door frames, between sole plates and floors, between
If your home meets all of the three criteria above, you must provide additional fresh air. See Ventilation Air From Outdoors, page 7.
If your home does not meet all of the three cri- teria above, proceed to Determining
Confined and Unconfined Space
The National Fuel Gas Code ANS Z223.1/NFPA 54 defines a confined space as a space whose volume is less than 50 cubic feet per 1,000 Btu per hour (4.8 m3 per kw) of the aggregate input rating of all appliances installed in that space and an unconfined space as a space whose volume is not less than 50 cubic feet per 1,000 Btu per hour (4.8 m3 per kw) of the aggregate input rating of all appliances installed in that space. Rooms com- municating directly with the space in which the appliances are installed*, through openings not furnished with doors, are considered a part of the unconfined space.
This heater shall not be installed in a confined space or unusually tight construction unless provi- sions are provided for adequate combustion and ventilation air.
*Adjoining rooms are communicating only if there are doorless passageways or ventilation grills between them.
DETERMINING FRESH-AIR FLOW FOR Firebox LOCATION
Determining if You Have a Confined or
Unconfined Space
Use this work sheet to determine if you have a confined or unconfined space.
Space: Includes the room in which you will install heater plus any adjoining rooms with doorless passageways or ventilation grills between the rooms.
1.Determine the volume of the space (length x width x height).
Length x Width x Height =__________cu. ft.
(volume of space)
Example: Space size 22 ft. (length) x 18 ft. (width) x 8 ft. (ceiling height) = 3168 cu. ft.
(volume of space)
If additional ventilation to adjoining room is supplied with grills or openings, add the volume of these rooms to the total volume of the space.
2.Multiply the space volume by 20 to determine the maximum Btu/Hr the space can support.
___________ (volume of space) x 20 = (Maxi- mum Btu/Hr the space can support)
Example: 3168 cu. ft. (volume of space) x 20 = 63,360 (maximum Btu/Hr the space can support)
3.Add the Btu/Hr of all fuel burning appliances in the space.
Gas water heater* | ______________Btu/Hr |
Gas furnace | ______________Btu/Hr |
Vented gas heater | ______________Btu/Hr |
Gas fireplace logs | ______________Btu/Hr |
Other gas appliances* | +____________Btu/Hr |
Total | =____________Btu/Hr |
*Do not include
Example: |
| 40,000 |
|
Gas water heater |
| Btu/Hr | |
Gas firebox logs | + | 39,000 | Btu/Hr |
Total | = | 79,000 | Btu/Hr |
4.Compare the maximum Btu/Hr the space can support with the actual amount of Btu/Hr used.
__________Btu/Hr (maximum the space can support)
__________Btu/Hr (actual amount of Btu/Hr used) Example: 63,360 Btu/Hr (maximum the space
can support)
79,000 Btu/Hr (actual amount of Btu/Hr used)
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