036-21603-002 Rev. A (1004)

FILTER PERFORMANCE

The airflow capacity data published in the “Blower Perfor- mance” table listed above represents blower performance WITHOUT filters. To determine the approximate blower per- formance of the system, apply the filter drop value for the fil- ter being used or select an appropriate value from the “Filter Performance” table shown below.

FILTER PERFORMANCE - PRESSURE DROP INCHES W.C.

NOTE: The filter pressure drop values in the “Filter Perfor- mance” table shown below are typical values for the type of filter listed and should only be used as a guideline. Actual pressure drop ratings for each filter type vary between filter manufacturer.

Airflow

Minimum Opening Size

 

 

Filter Type

 

 

Disposable

WASHABLE FIBER*

Pleated

Range

 

 

 

 

 

 

 

 

 

 

 

1 Opening

2 Openings

1 Opening

2 Openings

1 Opening

2 Openings

1 Opening

2 Openings

CFM

In³

In³

inwc

inwc

inwc

inwc

inwc

inwc

0 - 750

230

 

0.01

 

0.01

 

0.15

 

751 - 1000

330

 

0.05

 

0.05

 

0.2

 

1001 - 1250

330

 

0.1

 

0.1

 

0.2

 

1251 - 1500

330

 

0.1

 

0.1

 

0.25

 

1501 - 1750

380

658

0.15

0.09

0.14

0.08

0.3

0.17

1751 - 2000

380

658

0.19

0.11

0.18

0.1

0.3

0.17

2001 & Above

463

658

0.19

0.11

0.18

0.1

0.3

0.17

* Washable fiber are the type supplied with furnace (if supplied).

APPLYING FILTER PRESSURE DROP TO DETERMINE SYSTEM AIRFLOW

To determine the approximate airflow of the unit with a filter in place, follow the steps below:

1.Select the filter type.

2.Select the number of return air openings or calculate the return opening size in square inches to determine the proper filter pressure drop.

3.Determine the External System Static Pressure (ESP) without the filter.

4.Select a filter pressure drop from the table based upon the num- ber of return air openings or return air opening size and add to the ESP from Step 3 to determine the total system static.

5.If total system static matches a ESP value in the airflow table (i.e. 0.20 w.c. (50 Pa), 0.60 w.c. (150 Pa), etc,) the system air- flow corresponds to the intersection of the ESP column and Model/Blower Speed row.

6.If the total system static falls between ESP values in the table (i.e. 0.58 w.c. (144 Pa), 0.75 w.c. (187 Pa), etc.), the static pres- sure may be rounded to the nearest value in the table determin- ing the airflow using Step 5 or calculate the airflow by using the following example.

Example: For a 130,000 BTUH (38.06 kW) furnace with 2 return openings and operating on high-speed blower, it is found that total system static is 0.58” w.c. To determine the system airflow, complete the following steps:

Obtain the airflow values at 0.50 w.c. (125 Pa) & 0.60 w.c. (150 Pa) ESP.

Airflow @ 0.50”: 2125 CFM (60.17 m3/min)

Airflow @ 0.60”: 2035 CFM (57.62 m3/min)

Subtract the airflow @ 0.50 w.c. (125 Pa) from the airflow @ 0.60 w.c. (150 Pa) to obtain airflow difference.

2035 - 2125 = -90 CFM (2.55 m3/min)

Subtract the total system static from 0.50 w.c. (125 Pa) and divide this difference by the difference in ESP values in the table, 0.60 w.c. (150 Pa) - 0.50 w.c. (125 Pa), to obtain a percentage.

(0.58 - 0.50) / (0.60 - 0.50) = 0.8

Multiply percentage by airflow difference to obtain airflow reduction. (0.8) X (-90) = -72

Subtract airflow reduction value to airflow @ 0.50 w.c. (125 Pa) to obtain actual airflow @ 0.58 inwc (144 Pa) ESP.

2125 - 72 = 2053

UNIT CLEARANCES TO COMBUSTIBLES (ALL DIMENSIONS IN INCHES)

(ALL SURFACES IDENTIFIED WITH THE UNIT IN AN UPFLOW CONFIGURATION)

APPLICATION

TOP

FRONT

REAR

LEFT SIDE

RIGHT SIDE

FLUE

FLOOR/

CLOSET

ALCOVE

ATTIC

LINE

In.

In.

In.

In. (cm)

In. (cm)

In. (cm)

BOTTOM

CONTACT

 

 

 

 

 

 

 

 

 

 

 

 

UPFLOW

1

6

0

0

31

6

COMBUSTIBLE

YES

YES

YES

NO

UPFLOW B-VENT

1

3

0

0

0

1

COMBUSTIBLE

YES

YES

YES

NO

 

 

 

 

 

 

 

 

 

 

 

 

HORIZONTAL

32

6

0

1

0

6

COMBUSTIBLE

NO

YES

YES

YES3

HORIZONTAL B-VENT

0

3

0

1

0

1

COMBUSTIBLE

NO

YES

YES

YES3

114-1/2” cabinet models only. All other units “0” clearance.

214-1/2” cabinet left airflow applications only. All other units and right hand airflow applications “0” clearance.

3Line contact only permitted between lines formed by the intersection of the rear panel and side panel (top in horizontal position) of the furnace jacket and building joists, studs or framing.

6

Unitary Products Group

Page 6
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Coleman LC8T Filter Performance, Applying Filter Pressure Drop to Determine System Airflow, Washable Fiber, Bottom Contact

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