MB39A105
Example:
L ≥ | VIN (Max) | 2 | ton |
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2IOVO |
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≥ | 42 |
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| ⋅ | 9−4 | ⋅ | 1 |
2 ⋅ 0.25 ⋅ 9 | 9 | 500 ⋅ 103 |
≥3.95 ∝H
Inductance values derived from the above formulas are values that provide sufficient margin for continuous operation at maximum load current, but at which continuous operation is not possible at light loads. It is therefore necessary to determine the load level at which continuous operation becomes possible. In this application, the Sumida
Load current value under continuous operating conditions : IO
IO ≥ | VIN (Max) 2 |
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| 2LVO |
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≥ | 42 |
| ⋅ | 9−4 | ⋅ | 1 |
2 ⋅ 6.8 ⋅ 10−6 ⋅ 9 | 9 | 500 ⋅ 103 |
≥145.2 mA
To determine whether the current through the inductor is within rated values, it is necessary to determine the peak value of the ripple current as well as the
Peak value : IL
IL | ≥ |
| VO ⋅ IO | + |
| VIN | ton | ton = | VO − VIN | t | |
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| 2L | VO | |||||||
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ΔIL | = |
| VIN | ton |
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| L |
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Example: Using the
6.8 ∝H (allowable tolerance ±20%) , rated current = 1.4 A
Peak value:
IL ≥ |
| VO ⋅ IO | + |
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| VIN |
| ton | ton = |
| VO − VIN | t | |||
| VIN |
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| 2L |
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| VO | |||||||
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≥ |
| 9 ⋅ 0.25 |
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| 2.4 ⋅ | (9 − 2.4) | ⋅ | 1 |
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| 2.4 |
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| 2 ⋅ 6.8 | ⋅ 10−6 ⋅ 9 |
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| 500 ⋅ 103 |
≥1.20 A
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