2.You must use both coils of a dual
3.Most amplifiers deliver exactly the same amount of power bridged into a
English
SUGGESTED ENCLOSURES
MODELS SEALED BOX | VENTED BOX | |
Internal Volume | Internal Volume Qty. | Duct(s) Diameter x Length |
To design a subwoofer system that maximizes available amplifier power, keep the following rules in mind:
1.The total system impedance of woofers in parallel can be calculated using this formula:
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0.78 ft3 (22L) | ||
0.78 ft3 | (22L) | |
0.95 ft3 | (27L) | |
0.95 ft3 | (27L) | |
1.27 ft3 | (36L) |
1.13 ft3 (32L) | 1 | 2.95 in x 9.84 in (7.5cm x 25cm) | |
1.13 ft3 | (32L) | 1 | 2.95 in x 9.84 in (7.5cm x 25cm) |
1.7 ft3 | (48L) | 1 | 3.94 in x 8.66 in (10cm x 22cm) |
1.7 ft3 | (48L) | 1 | 3.94 in x 8.66 in (10cm x 22cm) |
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2.12 ft3 | (60L) | 2 | 3.94 in x 14.96 in (10cm x 38cm) |
Impedance = |
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1 | + | 1 | + | 1 | ... | ||||
| w | 1 | w | 2 | w | 3 | |||
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where w is the nominal impedance of the woofer.
2.The total system impedance of voice coils (or woofers) in series can be calculated using this formula:
Impedance = w1 + w2 + w3 ...
The diagrams below show parallel and series speaker connections.
Figure 1. Parallel connection | Figure 2. Series connection |
–The suggested enclosure volumes are related to only one speaker, including woofer and duct(s) displaced volume.
–For enclosures with more than one speaker, it is necessary to multiply the suggested volume and duct(s) by the quantity of speakers.
ENCLOSURES INTERNAL VOLUME
CALCULATION INSTRUCTIONS
RECTANGULAR BOX | TRAPEZOID RECTANGULAR BOX | |||||
Internal Volume = | A x B x C |
| A x B x ( | C + D | ) | |
1000 |
| Internal Volume = | 2 | |||
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| 1000 |
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– A, B and C are internal dimensions.