RH5RH
OPERATION OF STEP-UP DC/DC CONVERTER
The operation will be explained with reference to the following diagrams :
< Basic Circuits >< Current through L >
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| i2 |
| IL |
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| ILmax | |
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| L | SD | IOUT | ILmin | topen |
VIN | i1 |
| VOUT |
| t |
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| Lx Tr | CL |
| ton | toff |
T=1/fosc
Step 1 : LxTr is turned ON and current IL (= i1 ) flows, so that energy is charged in L. At this moment, IL(=i1 ) is increased from ILmin (= 0) to reach ILmax in proportion to the
Step 2 : When LxTr is turned OFF, Schottky diode (SD) is turned ON in order that L maintains IL at ILmax, so that current IL (= i2) is released.
Step 3 : IL (=i2) is gradually decreased, and in the case of discontinuous mode, IL reaches ILmin (=0) after a time period of topen, so that SD is turned OFF. However, in the case of a continuous mode which will be mentioned later,the time period (toff) runs out before IL reaches ILmin (=0), so that LxTr is turned ON in the next cycle, and SD is turned OFF. In this case, ILmin does not reach zero, and IL (=i1) increases from ILmin (> 0).
In the case of PWM control system, the output voltage is maintained constant by controlling the
•Discontinuous Conduction Mode and Continuous Conduction Mode
In the above two diagrams, the maximum value (ILmax) and the minimum value (ILmin) of the current which
flows through the inductor are the same as those when LxTr is ON and also when LxTr is OFF.
The difference between ILmax and ILmin, which is represented by | I, is : | |
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| Equation 1 |
wherein T=1/fosc=ton+toff
duty (%)=ton/T · 100=ton · fosc · 100 topen≤ toff
In Equation 1, VIN · ton/L and
10