MB39A105
■SELECTION OF COMPONENTS
• Nch MOS FET
The
Continuity loss : PC
PC = ID 2 ⋅ RDS(ON) ⋅ Duty
= VD (Max) ⋅ ID ⋅ tr ⋅ fOSC
6
PS (OFF) = | VD (Max) ⋅ ID (Max) ⋅ tf ⋅ fOSC | |
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Total loss : PT
PT = PC + PS (ON) + PS (OFF)
Example: Using the SANYO MCH3405
Input voltage VIN (Max) = 2.4 V, output voltage VO = 9 V, drain current ID = 0.94 A, Oscillation frequency fOSC = 500 kHz, L = 6.8 ∝H,
Drain current (Max) | : ID (Max) |
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ID (Max) | = |
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| VO ⋅ IO |
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| VIN(Min) | ton |
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| ton = |
| VO − VIN(Min) | t | |||||
| VIN(Min) |
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| 2L |
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| VO | |||||
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| 9 ⋅ 0.25 | + |
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| 2.4⋅ (9−2.4) |
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| 1 |
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| 2.4 |
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| 2 ⋅ 6.8 ⋅ 10−6 ⋅ 9 |
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| 500 | ⋅ 103 |
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| =: |
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| 1.20 (A) |
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Drain current (Min) | : ID (Min) |
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ID (Min) | = |
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| VO ⋅ IO |
| − | VIN(Min) | ton |
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| VIN(Min) |
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| 2L |
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| = |
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| 9 ⋅ 0.25 | − |
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| 2.4⋅ (9−2.4) |
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| 1 |
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| 2.4 |
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| 2 | ⋅ 6.8 ⋅ 10−6 ⋅ | 9 |
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| 500 ⋅ 103 |
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| =: | 0.68 (A) |
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