Installation Manual For Indoor Unit
The length difference among every duct is limited below 2:1.
Reduce the length of duct as possible as can.
Reduce the amount of bend as possible as can.
Use heat insulation material to bind and seal the part connecting main unit and the flare part of air discharging duct. Perform duct installation work, before the fitment of ceiling.
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7. Calculation method of the dimension of the simple quadrate air duct
Presuming the unit length friction impedance of the duct is 1Pa/m, when the dimension of one side of the air duct is fixed as 250mm, as shown below:
A | Air conditioner |
Air volume Duct(mmxmm)
B
A
A | 2400m3/h | 250x560 |
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B | 2000m3/h | 250x470 |
AStatic pressure box Equipped with air filter (bought)
The calculation of duct resistance (the simple calculation is as follow table)
Straight part | Calculate as per 1m length 1Pa, 1Pa/m |
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Bend part | Each bend takes as a3~4m long straight duct |
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Air out part | Calculate as 25Pa |
Static pressure box | Calculate as 50Pa/each |
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Air inlet grille (with air filter) | Calculate as 40Pa/each |
The chosen chart of simple duct
Note:1Pa/m=0.1mmAg/m |
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Shape | Square duct | |||
Item | Dimension | |||
Air volume | ||||
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m3/h(m3/n) | (mmxmm) | |||
100 | 250 | x | 60 | |
200 | 250 | x | 90 | |
300 | 250 | x | 120 | |
400 | 250 | x | 140 | |
500 | 250 | x | 170 | |
600(10) | 250 | x | 190 | |
800 | 250 | x | 230 | |
1,000 | 250 | x | 270 | |
1,200(20) | 250 | x | 310 | |
1,400 | 250 | x | 350 | |
1,600 | 250 | x | 390 | |
Shape | Square duct | |||
Item | Dimension | |||
Air volume | ||||
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m3/h(m3/n) | (mmxmm) | |||
1,800(30) | 250 | x | 430 | |
250 | x | 470 | ||
2000 | ||||
2400 | 250 | x | 560 | |
3,000(50) | 250 | x | 650 | |
3,500 | 250 | x | 740 | |
4,000 | 250 | x | 830 | |
4,500 | 250 | x | 920 | |
5,000 | 250 | x | 1000 | |
5,500 | 250 | x | 1090 | |
6,000(100) | 250 | x | 1180 | |
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