Philips TDA8542 1998 Apr 01 10, Fig.9 Po as a function of VCC., Fig.8 SVRR as a function of frequency., Fig.6 THD as a function of frequency., Fig.7 Channel separation as a function of frequency.

1998 Apr 01 10
Philips Semiconductors Product specification
2× 1 W BTL audio amplifier TDA8542
Fig.6 THD as a function of frequency.
Po= 0.5 W, Gv= 20 dB.
(1) VCC = 5 V, RL=8Ω.
(2) VCC = 9 V, RL=16Ω.
handbook, halfpage
10
1
10−1
10−2
MGD892
10 102103104
THD
(%)
f (Hz) 105
(1)
(2)
Fig.7 Channel separation as a function of
frequency.
VCC = 5 V, Vo= 2 V, RL=8Ω.
(1) Gv=30dB.
(2) Gv=20dB.
(3) Gv= 6 dB.
handbook, halfpage
−100
−90
−80
−70
−60
MGD893
10 10
2
10
3
10
4
10
5
f (Hz)
α
cs
(dB)
(1)
(2)
(3)
Fig.8 SVRR as a function of frequency.
VCC = 5 V, Rs=0Ω, Vr100 mV.
(1) Gv=30dB.
(2) Gv=20dB.
(3) Gv= 6 dB.
handbook, halfpage
−80
−60
−40
−20
MGD894
102 10 103
SVRR
(dB)
f (Hz)
104105
(1)
(2)
(3)
Fig.9 Po as a function of VCC.
(1) THD = 10%, RL=8Ω.
(2) THD = 10%, RL=16Ω.
handbook, halfpage
048
P
o
(W)
VCC (V) 12
2.5
0
2
1.5
1
(1) (2)
0.5
MGD895