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| Figure 6 |
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Set the CC switch down, and all others up. |
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Iin = 1/A x Iout |
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Iout = A x Vin |
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Where | Iout is the power supply output current in amps. | |||
| Iin is the programming current in μamps. | |||
| A is the gain. |
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| Model |
| A (A/μA) | 1/A (μV/A) |
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| E3614A |
| 0.055 | 18 |
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| E3515A |
| 0.0278 | 35.9 |
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| E3616A |
| 0.0158 | 63.4 |
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| E3617A |
| 0.00928 | 108 |
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Programming currents can be increased by adding a resistor across the CC+ and
Model | A (A/mV) | 1/A (mA/A) | Parallel resistor required for a | |
1 amp/mamp value of A (kohm) | ||||
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E3614A | 0.594 | 1.69 | 1.7 | |
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E3515A | 0.297 | 3.37 | 3.45 | |
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E3616A | 0.168 | 5.95 | 6.28 | |
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E3617A | 0.0989 | 1.01 | 11.2 | |
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Current Monitoring
Current of the power supply can be monitored across the internal current monitoring resistor. One side of the resistor is at the +output and A3; the other side of the resistor is at A1. The table below shows the resistor value and conversion factors. To obtain the current divide the measured voltage by the resistor value or multiply the amps/V times the voltage measured.
| Model | Resistor | amps/V |
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| E3614A | 0.1 | 10 |
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| E3515A | 0.2 | 5 |
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| E3616A | 0.6 | 1.67 |
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| E3617A | 0.89 | 1.12 |
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