hp40g+.book Page 24 Friday, December 9, 2005 1:03 AM

4.Copy the result and evaluate.

Thus, substituting X for S1, it can be seen that:

 

 

⎛

 

x3

⎞

2

 

⎜

 

----

⎟

 

 

3

∫3x – 5dx=

– 5x + 3

⎜

---------------⎟

⎜

∂

 

(X)

⎟

 

 

⎝

∂X

⎠

 

 

 

This result is derived from substituting X=S1 and X=0 into the original expression found in step 1. However, substituting X=0 will not always evaluate to zero and may result in an unwanted constant.

∫( )4 (x – 2 )5

To see this, consider: x – 2 dx= -------------------

5

The ‘extra’ constant of 32/5 results from the substitution of x = 0 into (x – 2)5/5, and should be disregarded if an indefinite integral is required.

Program constants and physical constants

When you press , three menus of functions and constants become available:

•the math functions menu (which appears by default)

•the program constants menu, and

•the physical constants menu.

The math functions menu is described extensively earlier in this chapter.

13-24

 

 

Using mathematical functions