hp40g+.book Page 27 Friday, December 9, 2005 1:03 AM
Solution 1 |
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Start by defining the | 1 | |
following: g(x) |
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= 2 – | ||
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| x + 2 |
Now type PROPFRAC(G(X)). Note that PROPFRAC can be found on the POLYNOMIAL submenu of the MATH menu.
Pressing 
yields the result shown at the right.
Solution 2
Enter the integral:
I = ∫20 g(x)dx .
Pressing 
yields the result shown at the right:
Pressing 
again yields:
Working by hand: |
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2x + 3 = 2(x + 2) – 1 , so: g(x) | = |
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2 – |
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| x + 2 |
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Then, integrating term by term between 0 and 2 |
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produces: |
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∫2 g(x)dx = [2x – ln(x + 2)] | x = 2 |
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0 |
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| x | = 0 |
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that is, since ln4 = 2 ln2 : |
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∫2 g(x)dx = 4 – ln2 |
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0 |
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