Table 4 – Electrical Data, Standard Motors
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| VOLTAGE | FAN MOTOR |
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UNIT | Hz{ | Hp (kW) |
| FLA | |||||
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| LIMITS |
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40RUA*25 | 60 | 253 | 5.0 (3.73) |
| 14.7/13.6 | ||||
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460 | 60 | 414 | 506 | 5.0 (3.73) |
| 6.8 | |||
40RUQ*25 |
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40RUS*25 | 575 | 60 | 518 | 632 | 5.0 (3.73) |
| 5.1 | ||
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40RUA*28 | 60 | 253 | 7.5 (5.59) |
| 21.4/19.4 | ||||
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460 | 60 | 414 | 506 | 7.5 (5.59) |
| 9.7 | |||
40RUS*28 |
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575 | 60 | 518 | 632 | 7.5 (5.59) |
| 7.8 | |||
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40RUA30 | 60 | 253 | 10.0 (7.46) |
| 28.0/25.2 | ||||
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460 | 60 | 414 | 506 | 10.0 (7.46) |
| 12.6 | |||
40RUS30 |
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575 | 60 | 518 | 632 | 10.0 (7.46) |
| 10.3 | |||
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POWER SUPPLY
Minimum | MOCP | |
Circuit Amps | ||
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18.4/17.0 | 30/25 | |
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8.5 | 15 | |
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6.4 | 15 | |
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26.9/24.3 | 45/40 |
12.120
9.8 | 15 |
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35.0/31.5 | 60/50 |
15.825
12.920
40RU
See Legend and Notes below.
Table 5 – Electrical Data, Alternate Motors
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| VOLTAGE | FAN MOTOR |
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UNIT | Hz{ |
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Hp (kW) |
| FLA | |||||||
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| LIMITS |
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40RUA*25 | 60 | 253 | 7.5 (5.59) |
| 21.4/19.4 | ||||
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460 | 60 | 414 | 506 | 7.5 (5.59) |
| 9.7 | |||
40RUQ*25 |
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40RUS*25 | 575 | 60 | 518 | 632 | 7.5 (5.59) |
| 7.8 | ||
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40RUA*28 | 60 | 253 | 10.0 (7.46) |
| 28.0/25.2 | ||||
40RUA*30 |
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460 | 60 | 414 | 506 | 10.0 (7.46) |
| 12.6 | |||
40RUS*28 |
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575 | 60 | 518 | 632 | 10.0 (7.46) |
| 10.3 | |||
40RUS*30 |
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POWER SUPPLY
Minimum | MOCP | |
Circuit Amps | ||
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26.9/24.3 | 45/40 |
12.120
9.8 | 15 |
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35.0/31.5 | 60/50 |
15.825
12.920
See Legend and Notes below.
Legend and Notes for Tables 4 and 5
LEGEND:
FLA | Full Load Amps | |
MOCP | Maximum Overcurrent Protection |
{Motors are designed for satisfactory operation within 10% of normal voltage shown. Voltages should not exceed the limits shown in the Voltage Limits column.
NOTES:
1.Minimum circuit amps (MCA) and MOCP values are calcu- lated in accordance with The NEC. Article 440.
2.Motor FLA values are established in accordance with Under- writers’ Laboratories (UL). Standard 1995.
3.Unbalanced
Never operate a motor where a phase imbalance in supply voltage is greater than 2%. Use the formula in the example (see column to the right) to determine the percentage of volt- age imbalance.
4.Installation with Accessory Electric Heaters
Size the Field Power Wiring between the heater TB1 and the 40RU indoor fan motor per NEC Article
Example: Supply voltage is
% Voltage Imbalance = 100 x | max voltage deviation from average voltage | |
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average voltage | ||
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AB = 393 v
BC = 403 v
AC = 396 v
Average Voltage = | (393 + 403 + 396) | = | 1192 | |
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3 | 3 | |||
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=397
Determine maximum deviation from average voltage. (AB) 397 – 393 = 4 v
(BC) 403 – 397 = 6 v (AC) 397 – 396 = 1 v Maximum deviation is 4 v.
Determine percent of voltage imbalance.
% Voltage Imbalance | = 100 x | 6 | |
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397 | |||
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| = 1.5% |
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This amount of phase imbalance is satisfactory as it is below the maximum allowable 2%.
IMPORTANT: If the supply voltage phase imbalance is more than 2%, contact your local electric utility company immediately.
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