Table 1 — Electrical Data — Units Without Optional Powered Convenience Outlet (cont)
| NOMINAL | VOLTAGE | COMPRESSOR |
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| POWER |
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| ELECTRIC HEAT | POWER SUPPLY | CRSINGLE | DISCONNECT |
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UNIT | RANGE | (EA.) | OFM | IFM | IFM |
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| SIZE | WIRING | ||||||||
POWER SUPPLY | EXHAUST |
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| PART |
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50PG |
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| FLA | FLA | TYPE | CRHEATER | NOMINAL |
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| FIG. NO. | ||||
RLA | LRA | FLA | MCA | MOCP† | NO.(NOTE3) | FLA | LRA | ||||||||||
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| PART NO. | FLA |
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| KW* |
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50PG03−16
239A00
240A00
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| Low | 241A00 |
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| |
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| 242A00 |
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| 243A00 |
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| 239A00 |
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| High | 240A00 |
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| 241A00 | |
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| |
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| 242A00 |
12 | 518 632 | 40.0 0.8 | 243A00 | ||
(cont) |
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| |
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| 239A00 |
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| Low | 240A00 |
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| 241A00 | |
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| |
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| 242A00 |
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| 3.0 | 243A00 |
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| |
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| 239A00 |
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| High | 240A00 |
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| 241A00 | |
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| 242A00 |
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| 243A00 |
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| LEGEND |
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FLA | − | Full Load Amps |
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HACR − | Heating, Air Conditioning and Refrigeration |
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IFM | − | Indoor − Fan Motor |
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LRA | − | Locked Rotor Amps |
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MCA | − | Minimum Circuit Amps |
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MOCP − | Maximum Overcurrent Protection |
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NEC | − | National Electrical Code |
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OFM | − | Outdoor−Fan Motor |
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RLA | − Rated Load Amps |
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*Heater capacity (kW) is based on heater voltage of 208 v, 240 v, or 480 v. If power distribu- tion voltage to unit varies from rated heater voltage, heater kW will vary accordingly.
†Fuse or HACR circuit breaker.
NOTES:
1.In compliance with NEC requirements for multimotor and combination load equip- ment (refer to NEC Articles 430 and 440), the overcurrent protective device for the unit shall be fuse or HACR breaker.
2.Unbalanced
Never operate a motor where a phase imbalance in supply voltage is greater than 2%. Use the following formula to determine the percentage of voltage imbalance.
max voltage deviation from average voltage
% Voltage Imbalance | = 100 x |
average voltage
|
| 20.1 | 20 |
| 21 | 124 |
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13.9 | 15.0 | 20.8 | 25 | 030A00 | 21 | 124 | 15 |
23.1 | 25.0 | 32.4 | 35 | 030A00 | 32 | 124 | 15 |
32.3 | 35.0 | 43.9 | 45 | 030A00 | 42 | 124 | 15 |
37.0 | 40.0 | 49.7 | 50 | 030A00 | 48 | 124 | 15 |
46.2 | 50.0 | 49.7 | 60 | 030A00 | 58 | 124 | 15 |
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| 18.6 | 20 |
| 20 | 142 |
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13.9 | 15.0 | 21.4 | 25 | 030A00 | 20 | 142 | 15 |
23.1 | 25.0 | 33.0 | 35 | 030A00 | 30 | 142 | 15 |
32.3 | 35.0 | 45.1 | 45 | 030A00 | 41 | 142 | 15 |
37.0 | 40.0 | 50.3 | 50 | 030A00 | 46 | 142 | 15 |
46.2 | 50.0 | 50.3 | 60 | 030A00 | 57 | 142 | 15 |
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| 21.1 | 25 |
| 23 | 110 |
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13.9 | 15.0 | 24.6 | 25 | 030A00 | 23 | 110 | 15 |
23.1 | 25.0 | 36.1 | 40 | 030A00 | 33 | 110 | 15 |
32.3 | 35.0 | 47.7 | 50 | 030A00 | 44 | 110 | 15 |
37.0 | 40.0 | 53.4 | 60 | 030A00 | 49 | 110 | 15 |
46.2 | 50.0 | 53.4 | 60 | 030A00 | 60 | 110 | 15 |
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| 21.1 | 25 |
| 23 | 110 |
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13.9 | 15.0 | 24.6 | 25 | 030A00 | 23 | 110 | 15 |
23.1 | 25.0 | 36.1 | 40 | 030A00 | 33 | 110 | 15 |
32.3 | 35.0 | 47.7 | 50 | 030A00 | 44 | 110 | 15 |
37.0 | 40.0 | 53.4 | 60 | 030A00 | 49 | 110 | 15 |
46.2 | 50.0 | 53.4 | 60 | 030A00 | 60 | 110 | 15 |
Example: Supply voltage is |
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AB = 224 v |
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BC = 231 v |
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AC = 226 v | 224 + 231 + 226 | |
Average Voltage = | ||
3 | ||
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=681
3
=227
Determine maximum deviation from average voltage.
Maximum deviation is 4 v.
Determine percent of voltage imbalance.
4
% Voltage Imbalance | = 100 x |
227
= 1.76%
This amount of phase imbalance is satisfactory as it is below the maximum allowable 2%. IMPORTANT: If the supply voltage phase imbalance is more than 2%, contact your local electric utility company immediately.
3.Single point kits CRSINGLE028A00 and CRSINGLE030A00 are not required if field−supplied pressure connectors are used.
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