Jotul F 500 operating instructions Parts List for the Oslo F500

PARTS LIST FOR THE OSLO F500

1ash door

2ash lip

3front door

4front

5right side

6left side

7side door

8rear plate

9top

10top cover

11bottom

12leg

13smoke outlet

14ash house

15ashpan

16inner bottom

17firegrate

18refractory brick

19air manifold

20tube frame holder

21bottom left tube holder

22upper left tube holder

23front tube

23middle tube

24rear tube

25bottom right tube holder

26upper right tube holder

27top burn plate

28insulating blanket (top)

*gasketing for top

*gasketing for top cover

29side burn plates 2 pcs

*insulating blanket for sides

30door glass

*glass gasketing

*glass clips

31inner front

32primary air lever

33air valve/slider

34inspection cover

optional equipment

40bottom heatshield

41rear heatshield

42top exit shield

APPENDIX A:

ALTERNATE FLOOR PROTECTION

All floor protection materials must be non-combustible ie. metal, brick, stone, mineral fiber boards). Any combustible material may not be used.

The easiest means of determining if a proposed alternate floor material meets requirements listed in this manual is to follow this procedure.

R-value = thermal resistance k-value = thermal conductivity C-value = thermal conductance

1.Convert the specification to R-value;

a.If R-value is given, no conversion is

needed.

b.If k-value is given with a required thickness (T) in inches: R=1/k X T.

c.If C-value is given: R=1/C.

2.Determine the R-value of the proposed alternate floor protector.

a.Use the formula in Step 1 to convert values not expressed as “R”.

b.For multiple layers, add R-values of each layer to determine overall R-value.

3.If the overall R-value of the sustem is greater than the R-value of the specified floor protector, the alternate is acceptable.

EXAMPLE:

The specified floor protector should be 3/4” thick material with a k-factor of 0.84. The proposed alternate is 4” brick with a C- factor of 1.25 over

1/8” mineral board witha k-factor of 0.29.

Step A. Use formula above to convert specifications to R-value. R=1/k X T= 1/.84 X .75 = .893

Step B. Calculate R of proposed system. 4” brick of C-1.25, therefore

R brick = 1/C = 1/1.25 = 0.80.

1/8” mineral board of k = 0.29 therefore R mineral board = 1/.29 X 0.125 = 0.431

Total R = R brick + R mineral board= 0.8 + 0.431=1.231

Step C. Compare proposed system R = 1.231 to specified R of 0.893. Since R is greater than required, the system is acceptable.

Definitions:

Thermal conductance =
	Btu		=	W
C = (hr)(ft2)(F)				(m2)(K)
Thermal conductivity =
k =	Btu	=		W	=	(Btu)
	(hr)(ft2)(F)			(m2)(K)		(hr)(ft)(F)
Thermal resistance =
	Btu		=	(m2)(K)		= (Btu)(inch)
R = (hr)(ft2)(F)				W		(hr)(ft2)(F)

FOR THE JØTUL OSLO F500 WOOD STOVE REQUIRES FLOOR PROTECTION WITH A MINIMUM INSULATING R

VALUE OF 0.5.

ALCOVE INSTALLATION REQUIRE A MINIMUM R VALUE OF 1.6. (IF A UL/ULC or WHI LISTED HEARTH PAD IS NOT USED.)

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