Altitude/Temperature Correction Factors

505430-BTG-A-0309

Altitude/Temperature Correction Factors

Air						Altitude (Ft.)
Temp.	0	1000	2000	3000	4000		5000	6000	7000	8000	9000	10000
40	1.060	1.022	0.986	0.950	0.916		0.882	0.849	0.818	0.788	0.758	0.729
50	1.039	1.002	0.966	0.931	0.898		0.864	0.832	0.802	0.772	0.743	0.715
60	1.019	0.982	0.948	0.913	0.880		0.848	0.816	0.787	0.757	0.729	0.701
70	1.000	0.964	0.930	0.896	0.864		0.832	0.801	0.772	0.743	0.715	0.688
80	0.982	0.947	0.913	0.880	0.848		0.817	0.787	0.758	0.730	0.702	0.676
90	0.964	0.929	0.897	0.864	0.833		0.802	0.772	0.744	0.716	0.689	0.663
100	0.946	0.912	0.880	0.848	0.817		0.787	0.758	0.730	0.703	0.676	0.651

	1.100
	1.050
	1.000
Factor	0.950						Sea Level
	0.950
	0.900						1000 ft
	0.900						2000 ft
Correction							2000 ft
	0.850						3000 ft
	0.850						4000 ft
							4000 ft
	0.800						5000 ft
	0.750						6000 ft
							6000 ft
							7000 ft
							7000 ft
	0.700						8000 ft
	0.700						9000 ft
							9000 ft
	0.650						10000 ft
	0.650
	0.600
	40	50	60	70	80	90	100
			Air Temperature (ºF)

Figure 1: Altitude/Temperature Correction Factors

The examples below will assist in determining the airflow performance of the product at altitude.

Example 1: What are the corrected CFM, static pressure, and BHP at an elevation of 5,000 ft. if the blower performance data is 6,000 CFM, 1.5 IWC and 4.0 BHP?

Solution: At an elevation of 5,000 ft. the indoor blower will still deliver 6,000 CFM if the rpm is unchanged. However, the Altitude/Temperature Correction Factors table must be used to determine the static pressure and BHP. Since no temperature data is given, we will assume an air temperature of 70°F. The table shows the correction factor to be 0.832.

Corrected static pressure = 1.5 x 0.832 = 1.248 IWC

Corrected BHP = 4.0 x 0.832 = 3.328

Example 2: A system, located at 5,000 feet of elevation, is to deliver 6,000 CFM at a static pressure of 1.5". Use the unit

blower tables to select the blower speed and the BHP requirement.

Solution: As in the example above, no temperature information is given so 70°F is assumed.

The 1.5" static pressure given is at an elevation of 5,000 ft. The first step is to convert this static pressure to equivalent sea level conditions.

Sea level static pressure = 1.5 / .832 = 1.80"

Enter the blower table at 6000 sCFM and static pressure of 1.8". The rpm listed will be the same rpm needed at 5,000 ft.

Suppose that the corresponding BHP listed in the table is 3.2. This value must be corrected for elevation.

BHP at 5,000 ft. = 3.2 x .832 = 2.66

68	Johnson Controls Unitary Products

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505430-BTG-A-0309