Jotul operating instructions F 3 CB PARTS LIST, Appendix A, Only Use Replacements Parts, 52 Leg

F 3 CB PARTS LIST

2Inner rear heatshield

2B Outer rear heatshield

6Smoke outlet cover

7Traverse bar

8Top plate with smoke cover

11 Baffle plate

12 Air distributor

15 Back plate

22 Side plate

23 Back burn plate

24 Right burn plate

26 Air deflector

28 Sliding air vent

29 Front plate

31 Log retainer

35 Door

37 Hinge pin

40 Start-up air vent

42 Door handle complete

43 Locking bar

45 Glass

46 Sparkscreen

51 Ashlip

52 Leg

55 Bottom plate

57 Inner bottom plate

59 Left burn plate

62 Secondary air cover

64 Flat ash housing gasket

65 Ash housing

70 Ashpan

76 Ashpan door

73 Stove tool

78 Door latch

79 Bottom heatshield

ONLY USE REPLACEMENTS PARTS

PROVIDED THROUGH YOUR AUTHORIZED JØTUL DEALER.

APPENDIX A:

ALTERNATE FLOOR PROTECTION

All floor protection materials must be non-combustible ie. metal, brick, stone, mineral fiber boards). Any combustible material may not be used.

The easiest means of determining if a proposed alternate floor material meets requirements listed in this manual is to follow this procedure.

R-value = thermal resistance k-value = thermal conductivity C-value = thermal conductance

1.Convert the specification to R-value;

a.If R-value is given, no conversion is

needed.

b.If k-value is given with a required thickness (T) in inches: R=1/k X T.

c.If C-value is given: R=1/C.

2.Determine the R-value of the proposed alternate floor protector.

a.Use the formula in Step 1 to convert values not expressed as “R”.

b.For multiple layers, add R-values of each layer to determine overall R-value.

3.If the overall R-value of the sustem is greater than the R-value of the specified floor protector, the alternate is acceptable.

EXAMPLE:

The specified floor protector should be 3/4” thick material with a k-factor of 0.84. The proposed alternate is 4” brick with a C- factor of 1.25 over

1/8” mineral board witha k-factor of 0.29.

Step A. Use formula above to convert specifications to R-value. R=1/k X T= 1/.84 X .75 = .893

Step B. Calculate R of proposed system. 4” brick of C-1.25, therefore

R brick = 1/C = 1/1.25 = 0.80.

1/8” mineral board of k = 0.29 therefore R mineral board = 1/.29 X 0.125 = 0.431

Total R = R brick + R mineral board= 0.8 + 0.431=1.231

Step C. Compare proposed system R = 1.231 to specified R of 0.893. Since R is greater than required, the system is acceptable.

Definitions:

Thermal conductance =
	Btu		=	W
C = (hr)(ft2)(F)				(m2)(K)
Thermal conductivity =
k =	Btu	=		W	=	(Btu)
	(hr)(ft2)(F)			(m2)(K)		(hr)(ft)(F)
Thermal resistance =
	Btu		=	(m2)(K)		= (Btu)(inch)
R = (hr)(ft2)(F)				W		(hr)(ft2)(F)

FOR THE JØTUL F 3 CB WOOD STOVE REQUIRES FLOOR PROTECTION WITH A MINIMUM INSULATING

R VALUE OF 1.1.

ALCOVE INSTALLATION REQUIRE A MINIMUM R VALUE OF 1.1. (IF A UL/ULC or WHI LISTED HEARTH PAD IS NOT USED.)

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