Regency I1200S Installation, Masonry And Factory Built Fireplace Clearances, Adjacent, Mantle

INSTALLATION

MASONRY AND FACTORY BUILT FIREPLACE CLEARANCES

The minimum required clearances to combustible materials when installed into a masonry or factory built fi replace are listed below.

	Adjacent	Mantle**	Top	Side	Minimum	Minimum	Minimum
Unit	Side Wall	(to Top)	Facing	Facing	Hearth	Hearth	Hearth Side
	(to Side)		(to Top)	(to Side)	Extension*	Thickness*	Extension
	A	B	C	D	E	F	G

I1200S 15" (381mm) 20" (508mm) 14" (356mm) 7.375"(187mm) 16" (406mm) 1.5" (38mm) 8" (203mm)

Side and Top facing is a maximum of 1.5" thick. Floor protection must non-combustible, insulative material with an R value of 1.1 or greater.

* If the hearth extension is fl ush with the fl oor (F) it must extend 19.5" in front of the body face

(E).

Note: Hearth Extension Width (G) is meas- ured from edge of fuel door to side of hearth.

** A non-combustible mantel may be installed at a lower height if the framing is made of metal studs covered with a non-combustible board.

Floor Protection

Please check to ensure that your floor protection and hearth will meet the standards for clearance to combustibles. Your hearth extension must be made from a non-combustible material.

Clearance diagram for installations

HOW TO DETERMINE IF ALTERNATE

FLOOR PROTECTION MATERIALS ARE ACCEPTABLE

The specifi ed floor protector should be 3/8" (18mm) thick material with a K - factor of 0.84.

The proposed alternative is 4" (100mm) brick with a C-factor of 1.25 over 1/8" (3mm) mineral board with a K-factor of 0.29.

Step (a):

Use formula above to convert specifi cation to R-value.

R = 1/k x T = 1/0.84 x .75 = 0.893.

Step (b):

Calculate R of proposed system. 4" brick of C = 1.25, therefore Rbrick = 1/C = 1/1.25 = 0.80

1/8" mineral board of k = 0.29, therefore Rmin.bd. = 1/0.29 x 0.125 = 0.431 Total R = Rbrick + Rmineral board = 0.8 + 0.431 = 1.231.

Step (c):

Compare proposed system R of 1.231 to specified R of 0.893. Since proposed system R is greater than required, the system is acceptable.

DEFINITIONS

Thermal Conductance:

C	=	Btu		=	W
		(hr)(ft2 )(oF)			(m2))(K)
Thermal Conductivity:
k	= (Btu)(inch)		=	W	= Btu
(hr)(ft3)(oF)			(m)(K)		(hr)(ft)(oF)
Thermal Resistance:
R	= (ft2)(hr)(oF)		=	(m2)(K)
		Btu		W

8 I1200 Regency Wood Insert