7.0: Applications (continued)
PSIM-AC PSIM-DC PSIM-5V
The
Total Voltage drop =
=(2 x 12 x [3+1]) + 0.04 (1+2+3+4+5+6+7+8+9+10+11+12)+ (15.2 x 6) + 0.04 (1+2+3+4+5+6)
=96 + 3.12 + 91.2 + 0.84
=191 mV
Then approximate voltage at end of network | = | nominal supply voltage - calculated volt drop | |
| = | 5.25 | - 0.191 |
| = 5.06 | V |
i.e. greater than 4.75 Vdc the minimum working voltage. In this example the input supply to the
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