Hampton Direct HI300 installation manual Masonry and Factory Built Fireplace Clearances, Step b

INSTALLATION

MASONRY AND FACTORY BUILT FIREPLACE CLEARANCES

The minimum required clearances to combustible materials when installed into a masonry or factory built fi replace are listed below.

	Adjacent	Mantle**	Top	Side	Minimum	Minimum	Minimum
Unit	Side Wall	(to Top)	Facing	Facing	Hearth	Hearth	Hearth Side
	(to Side of unit)		(to Top)	(to Side of unit)	Extension*	Thickness*	Extension
	A	B	C	D	E	F	G
Wood Cast
Insert (HI300)	11"/280mm	20"/508mm	12"/305mm	8"/200mm	18"/455mm	0.5"/13mm	8"/200mm

Side and Top facing is a maximum of 1.5" thick. Floor protection must be non-combustible, insula- tive material with an R value of 1.1 or greater.

*Hearth thickness of 0.5" with k value = 0.84", R value = 0.6 or greater.

Thermal fl oor protection not required if unit is raised 3.5" min. measured from bottom of stove. At this point the standard ember fl oor protection will be required. It will need to be a non-combustible material that covers 16" (406 mm) to the front of the unit (in Canada 18" (450 mm) and 8" (200 mm) to the sides.

All fl oor protection must be non-combustible (i.e., metals, brick, stone, mineral fi ber boards, etc.)Any organic materials (i.e. plastics, wood paper prod- ucts, etc.) are combustible and must not be used. The fl oor protection specifi ed includes some form of thermal designation such as R-value (thermal resistance) or k-factor (thermal conductivity).

**Anon-combustible mantel may be installed at a lower height if the framing is made of metalstudscoveredwithanon-combustible board.

Clearance Diagram for Installations

**Max. mantle depth is 10" (254mm)

Minimum Hearth Extension for the front (E) and sides

(G) are measured from the fuel door opening.

HOW TO DETERMINE IF ALTERNATE

FLOOR PROTECTION MATERIALS ARE ACCEPTABLE

The specifi ed fl oor protector should be 3/8" (18mm) thick material with a K - factor of 0.84.

The proposed alternative is 4" (100mm) brick with a C-factor of 1.25 over 1/8" (3mm) mineral board with a K-factor of 0.29.

Step (a):

Use formula above to convert specifi cation to R-value.

R = 1/k x T = 1/0.84 x .75 = 0.893.

Step (b):

Calculate R of proposed system. 4" brick of C = 1.25, therefore Rbrick = 1/C = 1/1.25 = 0.80

1/8" mineral board of k = 0.29, therefore Rmin.bd. = 1/0.29 x 0.125 = 0.431 Total R = Rbrick + Rmineral board = 0.8 + 0.431 = 1.231.

Step (c):

Compare proposed system R of 1.231 to specified R of 0.893. Since proposed system R is greater than required, the system is acceptable.

DEFINITIONS

Thermal Conductance:

C	=	Btu	=	W
		(hr)(ft2 )(oF)		(m2))(K)

Thermal Conductivity:

k =	(Btu)(inch) =	W	= Btu
	(hr)(ft3)(oF) (m)(K)		(hr)(ft)(oF)
Thermal Resistance:
R	= (ft2)(hr)(oF)	=	(m2)(K)
	Btu		W

Hampton HI300 Wood Cast Insert 7