where X is distance, V0 is initial velocity, T is time, and A is acceleration. This is actually two equations, Y = X and Y = V0 T + (AT 2) / 2.

Since this equation is quadratic for T, there can be both a positive and a negative solution. However, we are concerned only with positive solutions, since only positive distance makes sense.

1.Select the Solve aplet and enter the equation.

Select Solve

X

V

T

A

T 2

2.Find the solution for T (time) when X=30, V=2, and A=4. Enter the values for X, V, and A; then highlight the independent variable, T.

30

2

4

to highlight T

3.Use the Plot view to find an initial guess for T. First set

appropriate X and Y ranges in the Plot Setup. With equation X = V x T + A x T 2 /2, the plot will produce

two graphs: one for Y = X and one for

X = V x T + A x T 2 /2. Since we have set X = 30 in this example, one of the graphs will be Y = 30 . Therefore, make the YRNG 5 to 35. Keep the XRNG default of – 6.5 to 6.5.

SETUP-PLOT

5 35

4.Plot the graph.

7-8

Solve aplet

Page 92
Image 92
HP 39g+ Graphing manual To highlight T, Plot the graph