Napoleon Fireplaces GE38NT-M, GE38PT-M manual 90 H2 H3

9

TOP EXIT / HORIZONTAL TERMINATION

when (Ht) > (Vt) FIGURE 7 Example 3:

Simple venting configuration (only one 90° elbow)

See graph to determine the required ver- tical rise VT for the required horizontal run HT.

V1

90°

H1 H4 V2

90° H2 H3

FIGURE 9

REQUIRED

VERTICAL

RISE IN

INCHES

VT

HORIZONTAL VENT RUN PLUS OFFSET IN FEET HT

The shaded area within the lines represents acceptable values for HT and VT .

For vent configurations requiring more than one 90° elbow the following formulas apply:

Formula 1: HT < 4.2 VT
Formula 2: HT + VT	< 24.75 feet
	H1	H2
Example 2:

V1 90°

FIGURE 8

V1	= VT	= 6 ft
H1	= 3 ft
H2	= 5 ft
HR	= H1 + H2		= 3 + 5 = 8 ft
HO	= .03(two 90° elbows - 90°) = .03(180° - 90°) = 2.7 ft
HT	= HR + HO = 8 + 2.7 = 10.7 ft

HT + VT = 10.7 + 6 =16.7

Formula 1: HT < 4.2 VT

4.2VT = 4.2 x 6 = 25.2 ft

10.7< 25.2

Formula 2: HT + VT < 24.75 feet 16.7 < 24.75

Since both formulas are met, this vent configuration is ac- ceptable.

V1	= 4 ft
V2	= 1.5 ft
VT	= V1 + V2 = 4 + 1.5 = 5.5 ft
H1	= 2 ft
H2	= 1 ft
H3	= 1 ft
H4	= 1.5 ft
HR	= H1 + H2 + H3 + H4 = 2 + 1 + 1 + 1. 5 = 5.5 ft
HO	= .03(four 90° elbows - 90°) = .03(360° - 90°) = 8.1 ft
HT	= HR + HO = 5.5 + 8.1 = 13.6 ft

HT + VT = 13.6 + 5.5 = 19.1 ft

Formula 1: HT < 4.2 VT

4.2VT = 4.2 x 5.5 = 23.1 ft

13.6< 23.1

Formula 2: HT + VT < 24.75 feet

19.1 < 24.75

Since both formulas are met, this vent configuration is ac- ceptable.

W415-0429 / C / 11.04.05