| Table 8 — Electrical Data — | 60 Hz Units |
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UNIT | FACTORY- | NOMINAL | VOLTAGE | COMPRESSOR | FAN MOTORS | POWER | |||||
VOLTAGE | RANGE‡ | SUPPLY | |||||||||
SIZE | INSTALLED |
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38AUQ | OPTION | MIN | MAX | RLA | LRA | FLA (ea) | QTY | MCA | MOCP | ||
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| NONE OR DISCONNECT | 187 | 253 | 19.0 | 123 | 1.5 | 2 | 26.8 | 45 | ||
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| CONVENIENCE OUTLET | 31.6 | 50 | ||||||||
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*07 | NONE OR DISCONNECT | 414 | 506 | 9.7 | 62 | 0.9 | 2 | 13.9 | 20 | ||
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CONVENIENCE OUTLET | 16.1 | 25 | |||||||||
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| NONE OR DISCONNECT | 518 | 633 | 7.4 | 50 | 0.6 | 2 | 10.5 | 15 | ||
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| CONVENIENCE OUTLET | 12.2 | 15 | ||||||||
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| NONE OR DISCONNECT | 187 | 253 | 25.0 | 164 | 1.5 | 2 | 34.3 | 50 | ||
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| CONVENIENCE OUTLET | 39.1 | 60 | ||||||||
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*08 | NONE OR DISCONNECT | 414 | 506 | 12.2 | 100 | 0.9 | 2 | 17.1 | 25 | ||
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CONVENIENCE OUTLET | 19.3 | 30 | |||||||||
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| NONE OR DISCONNECT | 518 | 633 | 9.0 | 78 | 0.6 | 2 | 12.5 | 20 | ||
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| CONVENIENCE OUTLET | 14.2 | 20 | ||||||||
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| NONE OR DISCONNECT | 187 | 253 | 30.1 | 225 | 1.5 | 2 | 40.6 | 60 | ||
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| CONVENIENCE OUTLET | 45.4 | 60 | ||||||||
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*12 | NONE OR DISCONNECT | 414 | 506 | 16.7 | 114 | 0.8 | 2 | 22.5 | 30 | ||
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CONVENIENCE OUTLET | 24.7 | 30 | |||||||||
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| NONE OR DISCONNECT | 518 | 633 | 12.2 | 80 | 0.6 | 2 | 16.5 | 25 | ||
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| CONVENIENCE OUTLET | 18.2 | 30 | ||||||||
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| LEGEND |
FLA | — | Full Load Amps |
LRA | — | Locked Rotor Amps |
MCA | — | Minimum Circuit Amps |
MOCP — | Maximum Overcurrent | |
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| Protection |
NEC | — | National Electrical Code |
RLA | — | Rated Load Amps |
‡Units are suitable for use on electrical systems where voltage supplied to the unit terminals is not below or above the listed limits.
NOTES:
1.The MCA and MOCP values are calculated in accordance with the NEC, Article 440.
2.Motor RLA and LRA values are established in accordance with Underwriters’ Laboratories (UL), Standard 1995.
3.The
4.Convenience outlet is available as a
5.Unbalanced
Never operate a motor where a phase imbalance in supply voltage is greater than 2%. Use the following formula to determine the percentage of voltage imbalance.
max voltage deviation from average voltage
% Voltage Imbalance = 100 x
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Example: Supply voltage is | ||||
AB = 224 v |
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BC = 231 v |
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AC = 226 v |
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(224 + 231 + 226) | 681 | |||
Average Voltage = |
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3 | 3 | |||
=227
Determine maximum deviation from average voltage. (AB) 227 – 224 = 3 v
(BC) 231 – 227 = 4 v (AC) 227 – 226 = 1 v Maximum deviation is 4 v.
Determine percent of voltage imbalance.
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% Voltage Imbalance | = 100 x |
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227
= 1.76%
This amount of phase imbalance is satisfactory as it is below the maximum allowable 2%.
IMPORTANT: If the supply voltage phase imbalance is more than 2%, contact your local electric utility company immediately.
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