
First, find on the
Downhill m
20
41
5 2
6
3
7Uphill
4
m | m | |
20 | 20 | |
19 | 19 | |
18 | ||
| ||
17 | 18 | |
16 |
|
at the point of intersection. In this procedure the slope angle can be neglected as the
8
9
10
11
5
6
7
15 | 17 |
| |
14 | 16 |
13 |
|
12 | 15 |
| |
11 | 14 |
|
the ground slope angle and the average eye level height of 1.6 m [5.5 ft] have
12 8
10 | 13 |
been taken into account.
13
14
15
16
17
18
19
20
21
9
10
11
12
13
14
15
16
9 | 12 |
8 | 11 |
| |
7 |
|
| 10 |
6 |
|
| 9 |
5 |
|
| 8 |
4 |
|
Corrected height | 7 |
| |
| 6 |
18 | Fig. 12. | Base reading |
|
Apparent height |