NOTES: Wiring between generator andelectrical appliances
1.Allowable current of cable
Useacable with anallowable current that is higherthan the rated input current of the load (electrical appliance). If the input current is higher thanthe allowable current of the cable used,the cable will become excessively heated anddeteriorate the insulation, possibly burningit out.
Table
2.Cable length
If a long cable is used, a voltage drop occurs due to the increased resistance in the conductors decreasing the input voltage to the load (electrical product). As a result, the load can be damaged. Table
area |
|
|
| Gauge No.; | . Resistance |
| Voltage drop per 100 m |
| I | |||||
|
|
|
| Ohm/100 | 1 1 A i 3 A | 5 | A I |
|
|
|
| |||
Sectional I |
|
|
|
| I |
|
|
| ||||||
mm2 | i |
|
| No.i'mm |
|
|
|
|
| 8A | 10A j | 12A | 15A | |
0.75 |
| 7 |
| 3010.18 | 2.477 | ! 2.5V | 8V | 12.5V |
| ! |
|
|
| |
1.2550i0I .18 12 |
|
| 1.486 |
| 5V | 17..5V 18V15V12V | 18V15V |
|
| |||||
2.0 | ' | 17 | : | 37/0.26 |
| 1 .OV | 3V | 5.0V | 8V | 10V | 12V | 15V | ||
|
|
| I |
|
|
|
|
|
| 8Vi | 1OV | 12V | 7.5V | |
| , | 23 | 45 / 0.32 | 0.517 |
| I 1.5V | 2.5V | 4V |
| 5V | 6.5V | |||
5.5 |
|
|
| 0.332 | j | l V b | 2Vi | 2.5V |
| 3 . 5 q | 4V | 5V | ||
|
|
|
|
|
| I |
|
| I - |
|
|
|
Table
VoltagedropindicatesasV =
R mens resistance ( 0 /lo0 m) on the above table. I means electric current through the wire (A).
imeans the length of the wire (m).
The length of wire indicates round length,it means twice the length from generator to electrical tools.
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