Table 5 — Electrical Data, Alternate Motors
UNIT | VOLTAGE |
| FAN MOTOR |
| POWER SUPPLY | ||||
LIMITS | Hp (kW) |
| FLA | Minimum | MOCP | ||||
|
|
|
| Circuit Amps | |||||
|
|
|
|
|
|
|
|
| |
|
| 2.4 | (1.79) |
| 11.0/11.0 | 13.8/13.8 | 20 | ||
|
| 2.9 | (2.16) |
| 7.5 | 9.4 | 15 | ||
40RM | 2.9 | (2.16) |
| 3.4 | 4.3 | 15 | |||
007 |
| 2.0 | (1.49) |
| 2.4 | 3.0 | 15 | ||
|
| 2.4 | (1.79) |
| 5.2 | 6.5 | 15 | ||
|
| 2.4 | (1.79) |
| 2.6 | 3.3 | 15 | ||
|
| 2.4 | (1.79) |
| 11.0 | 13.8 | 15 | ||
40RM |
| 2.9 | (2.16) |
| 7.5/7.5 | 9.4/9.4 | 15 | ||
40RMQ | 2.9 | (2.16) |
| 3.4 | 4.3 | 15 | |||
40RMS |
| 3.0 | (2.24) |
| 3.8 | 4.8 | 15 | ||
008 |
|
|
|
|
|
|
|
|
|
| 2.9 | (2.16) |
| 7.5 | 9.4 | 15 | |||
|
|
| |||||||
|
| 2.9 | (2.16) |
| 3.4 | 4.3 | 15 | ||
|
| 2.4 | (1.79) |
| 11.0 | 13.8 | 20 | ||
|
| 2.9 | (2.16) |
| 7.5 | 9.4 | 15 | ||
40RMS | 2.9 | (2.16) |
| 3.4 | 4.3 | 15 | |||
010 |
| 3.0 | (2.24) |
| 3.8 | 4.8 | 15 | ||
|
| 2.9 | (2.16) |
| 7.5 | 9.4 | 15 | ||
|
| 2.9 | (2.16) |
| 3.4 | 4.3 | 15 | ||
40RM |
| 3.7 | (2.76) |
| 10.5/10.5 | 13.3/13.3 | 20 | ||
| 3.7 | (2.76) |
| 4.8 | 6.0 | 15 | |||
40RMQ |
|
|
|
|
|
|
|
|
|
| 3.0 | (2.24) |
| 3.8 | 4.8 | 15 | |||
40RMS |
|
| |||||||
| 5.0 | (3.73) |
| 15.2 | 19.0 | 30 | |||
012 |
|
| |||||||
|
| 5.0 | (3.73) |
| 7.6 | 9.5 | 15 | ||
|
| 3.7 | (2.76) |
| 10.2 | 12.7 | 20 | ||
40RM |
| 3.7 | (2.76) |
| 4.8 | 6.0 | 15 | ||
40RMS |
| 5.0 | (3.73) |
| 5.1 | 6.4 | 15 | ||
014 |
| 5.0 | (3.73) |
| 15.2 | 19.0 | 30 | ||
|
|
| |||||||
|
| 5.0 | (3.73) |
| 7.6 | 9.5 | 15 | ||
40RM |
| 5.0 | (3.73) |
| 14.6/12.8 | 18.3/16.0 | 30/25 | ||
| 5.0 | (3.73) |
| 6.4 | 8.0 | 15 | |||
40RMQ |
|
|
|
|
|
|
|
|
|
| 5.0 | (3.73) |
| 5.1 | 6.4 | 15 | |||
40RMS |
|
| |||||||
| 5.0 | (3.73) |
| 15.2 | 19.0 | 30 | |||
016 |
|
| |||||||
|
| 5.0 | (3.73) |
| 7.6 | 9.5 | 15 | ||
40RM |
| 7.5 | (5.59) |
| 21.5/19.4 | 26.9/24.3 | 45/40 | ||
| 7.5 | (5.59) |
| 9.7 | 12.1 | 20 | |||
40RMQ |
|
|
|
|
|
|
|
|
|
| 7.5 | (5.59) |
| 7.8 | 9.8 | 15 | |||
40RMS |
|
| |||||||
| 7.5 | (5.59) |
| 22.8 | 28.5 | 50 | |||
024 |
|
| |||||||
|
| 7.5 | (5.59) |
| 11.4 | 14.3 | 25 | ||
40RM |
| 10.0 | (7.46) |
| 28.2/26.8 | 35.3/33.5 | 60/60 | ||
| 10.0 | (7.46) |
| 13.4 | 16.8 | 30 | |||
40RMQ |
|
|
|
|
|
|
|
|
|
| 10.0 | (7.46) |
| 10.3 | 12.9 | 20 | |||
40RMS |
|
| |||||||
| 10.0 | (7.46) |
| 32.2 | 40.3 | 60 | |||
028 |
|
| |||||||
|
| 10.0 | (7.46) |
| 16.1 | 20.1 | 30 |
Legend and Notes For Tables 4 and 5
| LEGEND |
FLA | — Full Load Amps |
MOCP | — Maximum Overcurrent Protection |
*Motors are designed for satisfactory operation within 10% of nominal volt- ages shown. Voltages should not exceed the limits shown in the Voltage Lim- its column.
Determine maximum deviation from average voltage.
(AB) 397 – 393 = 4 v (BC) 403 – 397 = 6 v (AC) 397 – 396 = 1 v
Maximum deviation is 6 v.
Determine percent voltage imbalance.
NOTES:
1. Minimum circuit amps (MCA) and MOCP values are calculated in accor- |
% Voltage Imbalance = 100 x
6
| dance with NEC (National Electrical Code), Article 440. |
2. | Motor FLA values are established in accordance with UL (Underwriters’ |
| Laboratories) Standard 1995. |
3. | Unbalanced |
| Never operate a motor where a phase imbalance in supply voltage is |
| greater than 2%. Use the following formula to determine the percentage of |
| voltage imbalance. |
max voltage deviation from average voltage
= 100 x
average voltage
EXAMPLE: Supply voltage is
AB = 393 v
BC = 403 v
AC = 396 v
393 + 403 + 396
Average Voltage =
3
1192
=
3 = 397
397
= 1.5%
This amount of phase imbalance is satisfactory because it is below the maxi- mum allowable 2%.
IMPORTANT: If the supply voltage phase imbalance is more than 2%, contact your local electric utility company immediately.
23