Director
Have we achieved our goal of sending all the TCP traffic to Monitor Port 2? Not quite. What happens when an TCP packet arrives from 192.186.10.0? It matches the filter at CAM address 1, so it is copied to Monitor Port 1. But that is all that happens; it does not go to Monitor Port 2. The flow is correctly shown in the following diagram.
Network Port 5 |
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CAM
Address Filter
1n1.5 ip_src=192.186.10.0 m.1
2n1.5 ip_proto=TCP m.2
lter add in_ports=n1.5 ip_src=192.186.10.0 action=redir redir_ports=m.1 lter add in_ports=n1.5 ip_proto=6 action=redir redir_ports=m.2
Figure 36: Correct flow diagram for two interacting filters
To achieve the desired result of sending all TCP traffic to Monitor Port 2, clear the existing filters (filter discard command) and create three new filters by entering:
filter add in_ports=n1.5 ip_src=192.186.10.0 ip_proto=6 action=redir redir_ports=m.1,m.2 filter add in_ports=n1.5 ip_src=192.186.10.0 action=redir redir_ports=m.1
filter add in_ports=n1.5 ip_proto=6 action=redir redir_ports=m.2 filter commit
The flow diagram now looks as follows.
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Network Port 5 | 192.186.10.0 |
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CAM
Address Filter
1n1.5 ip_src=192.186.10.0 ip_proto=TCP m.1,m.2
2n1.5 ip_src=192.186.10.0
3n1.5 ip_proto=TCP m.2
lter add in_ports=n1.5 ip_src=192.186.10.0 ip_proto=6 action=redir redir_ports=m.1,m.2 lter add in_ports=n1.5 ip_src=192.186.10.0 action=redir redir_ports=m.1
lter add in_ports=n1.5 ip_proto=6 action=redir redir_ports=m.2
Figure 37: Correct way to send all TCP traffic to Monitor Port 2
Now, packets that match both the IP address and protocol conditions will be copied to both Monitor ports, while packets that match only one of the conditions will be directed to the desired Monitor port.
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