AIR for Combustion Ventilation | Desa VMH26NRB, EFS26NRA, EFS26PRA

AIR FOR COMBUSTION

AND VENTILATION

Continued

Unusually tight construction is defined as construction where:

a.walls and ceilings exposed to the out- side atmosphere have a continuous water vapor retarder with a rating of one perm (6 x 10-11kg per pa-sec-m2) or less with openings gasketed or sealed and

b.weather stripping has been added on openable windows and doors and

c.caulking or sealants are applied to ar- eas such as joints around window and door frames, between sole plates and floors, between wall-ceiling joints, be- tween wall panels, at penetrations for plumbing, electrical, and gas lines, and at other openings.

If your home meets all of these three crite- ria, you must provide additional fresh air. See Ventilation Air From Outdoors, page 8. If your home does not meet all of the three criteria above,proceed to Determining Fresh- Air Flow For Fireplace Location, below.

Confined and Unconfined Space

The National Fuel Gas Code, ANSI Z223.1/NFPA 54 defines a confined space as a space whose vol- ume is less than 50 cubic feet per 1,000 Btu per hour (4.8 m3 per kw) of the aggregate input rating of all appliances installed in that space and an un- confined space as a space whose volume is not less than 50 cubic feet per 1,000 Btu per hour (4.8 m3 per kw) of the aggregate input rating of all ap- pliances installed in that space. Rooms communi- cating directly with the space in which the appli- ances are installed*, through openings not fur- nished with doors, are considered a part of the unconfined space.

*Adjoining rooms are communicating only if there are doorless passageways or ventilation grills be- tween them.

DETERMINING FRESH-AIR FLOW FOR FIREPLACE LOCATION

Determining if You Have a Confined or Unconfined Space

Use this work sheet to determine if you have a confined or unconfined space.

Space: Includes the room in which you will in- stall fireplace plus any adjoining rooms with doorless passageways or ventilation grills between the rooms.

1.Determine the volume of the space (length x width x height).

Length x Width x Height =__________cu. ft. (volume of space)

Example: Space size 16 ft. (length) x 14 ft. (width) x 8 ft. (ceiling height) = 1792 cu. ft. (vol- ume of space)

If additional ventilation to adjoining room is sup- plied with grills or openings, add the volume of these rooms to the total volume of the space.

2.Multiply the space volume by 20 to determine the maximum Btu/Hr the space can support.

__________ (volume of space) x 20 = (Maxi-

mum Btu/Hr the space can support)

Example: 1792 cu. ft. (volume of space) x 20 = 35,840 (maximum Btu/Hr the space can support)

3.Add the Btu/Hr of all fuel burning appliances in the space.

Vent-free fireplace	_________ Btu/Hr
Gas water heater*	_________ Btu/Hr
Gas furnace	_________ Btu/Hr
Vented gas heater	_________ Btu/Hr
Gas fireplace logs	_________ Btu/Hr
Other gas appliances*	+ ________ Btu/Hr
Total	= ________ Btu/Hr

*Do not include direct-vent gas appliances. Di- rect-vent draws combustion air from the outdoors and vents to the outdoors.

Example:

Gas water heater	30,000	Btu/Hr
Vent-free fireplace	10,000	Btu/Hr
Total	40,000	Btu/Hr

4.Compare the maximum Btu/Hr the space can support with the actual amount of Btu/Hr used.

________	Btu/Hr (maximum the space can support)
________	Btu/Hr (actual amount of Btu/Hr used)

Example: 35,840 Btu/Hr (maximum the space can support)

40,000 Btu/Hr (actual amount of Btu/Hr used)

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