1744/1743
Users Manual
Active power of logging interval per phase
Total active power on all three phases
| 1 | M | |
P = | ⋅ ∑ P | ||
| |||
| M | bas j | |
| j=1 |
Pbas j to 200 ms value
M: Number of 200 ms intervals per logging interval
3
Ptotal = ∑ Pk
k=1
Absolute value of the active power per interval per phase
Sum of the absolute values of the active power on all three phases
Apparent power based on RMS values of voltage and current. Basic values on 200 ms per phase
Apparent power per logging interval per phase
Total apparent power on three phases
Pk: Active power of the phase
k: Phase (k = 1, 2, 3)
|
| 1 |
| M |
|
| ||||||
P | = |
| ⋅ ∑ | P |
|
|
| |||||
|
|
|
|
|
| |||||||
betr |
| M |
| j=1 | bas j |
|
|
| ||||
|
|
|
|
|
|
|
|
| ||||
|
|
|
|
| 1 | M |
|
| ||||
P |
| = |
| ∑ |
| P | + P | + P | ||||
|
|
| ||||||||||
|
|
|
| |||||||||
betr total |
|
|
| M j=1 |
| bas1 | bas 2 | bas 3 | ||||
|
|
|
|
|
|
|
|
| ||||
Sbas | = Vbas .Ibas |
|
| |||||||||
| 1 |
|
| M |
|
| ||||||
S = |
| ⋅ ∑ Sbas j |
|
| ||||||||
M |
|
|
| |||||||||
|
| j=1 |
|
|
Sbas j: 200 ms value
M: Number of 200 ms intervals per logging interval
3
Stotal = ∑ Sk
K=1
k:Phase (k = 1, 2, 3)
42