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The variable ODETYPE
You will notice in the
Example 2 – Solving an equation with initial conditions. Solve
d2y/dt2 + 5y = 2 cos(t/2),
with initial conditions
y(0) = 1.2, y’(0) =
In the calculator, use:
[‘d1d1y(t)+5*y(t) = 2*COS(t/2)’ ‘y(0) = 6/5’ ‘d1y(0) =
‘y(t)’ `
DESOLVE
Notice that the initial conditions were changed to their Exact expressions, ‘y(0) = 6/5’, rather than ‘y(0)=1.2’, and ‘d1y(0) =
Note: To obtain fractional expressions for decimal values use function Q (See Chapter 5).
Press µµ to simplify the result. Use ˜@EDIT to see this result:
i.e.,
‘y(t) =
Press ``J @ODETY to get the string “Linear w/ cst coeff” for the ODE type in this case.
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