640 - 607
B is incorrect; this is not a true statement.
C is incorrect;
Steve McQuerry. Interconnecting Cisco Network Devices. (Cisco Press: 2000) pages
Q.173
Exhibit:
The exhibit shows an IP address and its subnet mask. What is the last available host address for this IP subnet?
A.172.20.7.255
B.172.20.7.197
C.172.20.7.190
D.172.20.7.129
E.172.20.255.255
Answer: C
Explanation: In order to determine the last available host you will need to draw a vertical line just after the last contiguous subnet mask 1 bit. On the next line write the address that it to the left of the line and then to the right of the line place all 1s in the remaining spaces until the last free space. Place a 0 in this place. Convert the binary to
In this case the binary would be:
10101100 00010100 00000111 10 111110 This converts to
172.20.7.190
Leading the way in IT testing and certification tools, www.testking.com
