SMSC COM20020 manual Selecting RAM Page Size, Transmit Sequence

Models: COM20020

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The pointer may now be read to determine how many transfers were completed.

The software flow for controlling the Configuration, Node ID, Tentative ID, and Next ID registers is generally limited to the initialization sequence and the maintenance of the network map.

Additionally, it is necessary to understand the details of how the other Internal Registers are used in the transmit and receive sequences and to know how the internal RAM buffer is properly set up. The sequence of events that tie these actions together is discussed as follows.

Selecting RAM Page Size

During normal operation, the 2K x 8 of RAM is divided into four pages of 512 bytes each. The page to be used is specified in the "Enable Transmit (Receive) from (to) Page fnn" command, where "nn" specifies page 0, 1, 2, or

3.This allows the user to have constant control over the allocation of RAM.

When the Offset bit "f" (bit 5 of the "Enable Transmit (Receive) from (to) Page fnn" command word) is set to logic "1", an offset of 256 bytes is added to the page specified. For example: to transmit from the second half of page 0, the command "Enable Transmit from Page fnn" (fnn=100 in this case) is issued by writing 0010 0011 to the Command Register. This allows a finer resolution of the buffer pages without affecting software compatibility. This scheme is useful for applications which frequently use packet sizes of 256 bytes or less, especially for microcontroller systems with

limited memory capacity. The remaining portions of the buffer pages which are not allocated for current transmit or receive packets may be used as temporary storage for previous network data, packets to be sent later, or as extra memory for the system, which may be indirectly accessed.

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If the device is configured to handle both long and short packets (see "Define Configuration" command), then receive pages should always be 512 bytes long because the user never knows what the length of the receive packet will be. In this case, the transmit pages may be made 256 bytes long, leaving at least 512 bytes free at any given time. Even if the Command Chaining operation is being used, 512 bytes is still guaranteed to be free because Command Chaining only requires two pages for transmit and two for receive (in this case, two 256 byte pages for transmit and two 512 byte pages for receive, leaving 512 bytes free). Please note that it is the responsibility of software to reserve 512 bytes for each receive page if the device is

configured to handle long packets. The COM20020 does not check page boundaries during reception. If the device is configured to handle only short packets, then both transmit and receive pages may be allocated as 256 bytes long, freeing at least 1KByte at any given time.

Even if the Command Chaining operation is being used, 1KByte is still guaranteed to be free because Command Chaining only requires two pages for transmit and two for receive (in this case, a total of four 256 byte pages, leaving 1K free).

The general rule which may be applied to determine where in RAM a page begins is as follows:

Address = (nn x 512) + (f x 256).

Transmit Sequence

During a transmit sequence, the microcontroller selects a 256 or 512 byte segment of the RAM buffer and writes into it. The appropriate buffer size is specified in the "Define Configuration" command. When long packets are enabled, the COM20020 interprets the packet as either a long or short packet, depending on whether the

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SMSC COM20020 manual Selecting RAM Page Size, Transmit Sequence