Table 4B Ð Electrical Data Ð 50SX Units
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| OUTDOOR- | INDOOR- |
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| AWG 60C |
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UNIT SIZE |
| VOLTAGE RANGE | COMPRESSOR | FAN | FAN | POWER SUPPLY | MAX WIRE | |||||
MIN WIRE | ||||||||||||
50SX |
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| MOTOR | MOTOR |
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| LENGTH (ft) | |||
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| SIZE | |||||
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| Min | Max | RLA | LRA | FLA | FLA | MCA | MOCP* |
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024 | 187 | 253 | 12.9 | 62.5 | 1.4 | 2.0 | 19.5 | 30 | 12 | 75 | ||
030 | 187 | 253 | 15.0 | 76.0 | 1.4 | 2.6 | 22.8 | 30 | 10 | 100 | ||
| 187 | 253 | 16.7 | 95.0 | 1.4 | 2.8 | 25.1 | 30 | 10 | 95 | ||
036 | 187 | 253 | 10.9 | 75.0 | 1.4 | 2.8 | 17.8 | 25 | 12 | 70 | ||
| 414 | 506 | 5.4 | 40.0 | 0.8 | 1.4 | 9.0 | 10 | 14 | 100 | ||
| 187 | 253 | 20.0 | 104.0 | 1.4 | 3.1 | 29.5 | 45 | 10 | 80 | ||
042 | 187 | 253 | 13.9 | 88.0 | 1.4 | 3.1 | 21.9 | 30 | 10 | 60 | ||
| 414 | 506 | 6.8 | 44.0 | 0.8 | 1.6 | 10.9 | 15 | 14 | 100 | ||
| 187 | 253 | 26.4 | 129.0 | 1.4 | 7.2 | 41.6 | 60 | 6 | 100 | ||
048 | 187 | 253 | 15.0 | 99.0 | 1.4 | 7.2 | 27.4 | 40 | 10 | 70 | ||
| 414 | 506 | 8.2 | 49.5 | 0.8 | 2.3 | 13.4 | 20 | 14 | 100 | ||
060 | 187 | 253 | 32.1 | 169.0 | 2.1 | 7.2 | 49.4 | 60 | 6 | 100 | ||
187 | 253 | 19.3 | 123.0 | 2.1 | 7.2 | 33.4 | 50 | 8 | 90 | |||
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| LEGEND |
AWG | Ð American Wire Gage |
BRKR | Ð Breaker |
CUL | Ð Canadian Underwriters' Laboratories |
FLA | Ð Full Load Amps |
HACR | Ð Heating, Air Conditioning and |
| Refrigeration |
LRA | Ð Locked Rotor Amps |
MCA | Ð Minimum Circuit Amps |
MOCP Ð Maximum Overcurrent Protection | |
NEC | Ð National Electrical Code |
RLA | Ð Rated Load Amps |
*Fuse or HACR Breaker. ²Carrier Scroll Compressor. **Copeland Scroll Compressor.
NOTES:
1.In compliance with NEC requirements for multimotor and combi- nation load equipment (refer to NEC Articles 430 and 440), the overcurrent protective device for the unit shall be fuse or HACR breaker. The CUL units may be fuse or circuit breaker.
2.Minimum wire size is based on 60 C copper wire. If other than 60 C wire is used, or if length exceeds wire length in table, de- termine size from NEC.
3.Unbalanced 3-Phase Supply Voltage
Never operate a motor where a phase imbalance in supply volt- age is greater than 2%. Use the following formula to determine the percentage of voltage imbalance.
% Voltage Imbalance
EXAMPLE: Supply voltage is
AB = 452 v
BC = 464 v
AC = 455 v
Average Voltage = | 452 + 464 + 455 | ||||
3 | |||||
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| = | 1371 | |||
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Determine maximum deviation from average voltage. | |||||
(AB) 457 ± 452 = 5 v |
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(BC) 464 ± 457 = 7 v |
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(AC) 457 ± 455 = 2 v |
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Maximum deviation is 7 v. |
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Determine percent of voltage imbalance. | |||||
% Voltage Imbalance = 100 x |
| 7 |
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457 |
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= 1.53% |
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This amount of phase imbalance is satisfactory as it is below the maximum allowable 2%.
IMPORTANT: If the supply voltage phase imbalance is more than 2%, contact your local electric utility company immediately.
max voltage deviation from average voltage
= 100 x
average voltage
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