NOTES : Wiring between generator and electrical appliances
1.Allowable current of cable
Use a cable with an allowable current that is higher than the rated input current of the load (electrical appliance). If the input current is higher than the allowable current of the cable used, the cable will become excessively heated and deteriorate the insulation, possibly burning it out. The table below shows cables and their allowable currents for your reference.
2.Cable length
If a long cable is used, a voltage drop occurs due to the increased resistance in the conductors decreasing the input voltage to the load (electrical product). As a result, the load can be damaged. The table below shows voltage drops per 30 meters of cable.
| Cross | Allowable | Cable |
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| sectional | Current | Resistance |
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| mm2 | A | Ω/100m |
| 5A | 10A | 15A | 20A |
| 25A | 30A | ||
| 1.25 | 12 | 1.486 |
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| 4.5V | 8.9V | ＊ | ＊ |
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| 2.0 | 17 | 0.952 |
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| 2.8V | 5.7V | 8.6V | ＊ |
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| 3.5 | 23 | 0.517 |
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| 1.6V | 3.1V | 4.7V | 6.2V |
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| 5.5 | 35 | 0.332 |
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| 1.0V | 2.0V | 3.0V | 4.0V |
| 5.0V | 6.0V | |
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Voltage drop indicates as | V= | 1 |
| x R x I x L | R : Resistance (Ω/100m) |
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100 |
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| I : Electric current (A) |
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| L : Length (m) |
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The length of wire (L) indicates round length, which is the length from the generator |
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to the electrical tools and back. |
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<Example> | R : Resistance | 1.25mm2=1.48Ω/100m |
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| I : Electric current 10A |
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| L : Length | 30m |
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The voltage drop of the case described above
V= 1.48Ω x 10A x (30m x 2) ≒ 8.9 (V) 100
