INSTRUCTION SET S3C8245/P8245/C8249/P8249
6-78
SBC — Subtract with Carry
SBC dst,src
Operation: dst ← dst – src – c
The source operand, along with the current value of the carry flag, is subtracted from the destination
operand and the result is stored in the destination. The contents of the source are unaffected.
Subtraction is performed by adding the two's-complement of the source operand to the destination
operand. In multiple precision arithmetic, this instruction permits the carry ("borrow") from the
subtraction of the low-order operands to be subtracted from the subtraction of high-order operands.
Flags: C: Set if a borrow occurred (src > dst); cleared otherwise.
Z: Set if the result is "0"; cleared otherwise.
S: Set if the result is negative; cleared otherwise.
V: Set if arithmetic overflow occurred, that is, if the operands were of opposite sign and the sign of
the result is the same as the sign of the source; cleared otherwise.
D: Always set to "1".
H: Cleared if there is a carry from the most significant bit of the low-order four bits of the result; set
otherwise, indicating a "borrow".
Format:
Bytes Cycles Opcode
(Hex) Addr Mode
dst src
opc dst | src 2 4 32 r r
6 33 rlr
opc src dst 3 6 34 R R
6 35 RIR
opc dst src 3 6 36 RIM
Examples: Given: R1 = 10H, R2 = 03H, C = "1", register 01H = 20H, register 02H = 03H, and register
03H = 0AH:
SBC R1,R2 →R1 = 0CH, R2 = 03H
SBC R1,@R2 →R1 = 05H, R2 = 03H, register 03H = 0AH
SBC 01H,02H →Register 01H = 1CH, register 02H = 03H
SBC 01H,@02H →Register 01H = 15H,register 02H = 03H, register 03H = 0AH
SBC 01H,#8AH →Register 01H = 95H; C, S, and V = "1"
In the first example, if working register R1 contains the value 10H and register R2 the value 03H, the
statement "SBC R1,R2" subtracts the source value (03H) and the C flag value ("1") from the
destination (10H) and then stores the result (0CH) in register R1.