Procedure and result of equipment selection

1.Procedure of equipment selection

a.Calculate cooling for every room.

b.Select an indoor unit to match the cooling load for every room from the table on page 10.

c.Select the outdoor module to match the indoor units selected in point b. Select the outdoor modules based on the critical factors and the combination rule. Choose a tentative outdoor module that will match the indoor units, and check whether the selection agrees with the combination rule. Perform the capacity correction based on the pipe length, system lift, indoor set temperature, outdoor temperature.

Then, make sure the corrected system cooling capacity satisfies the cooling load.

2.Equipment selection and capacity check

 

Air conditioning load

 

 

 

 

Equipment selection

 

 

 

 

 

 

Floor

Room No.

 

Indoor air conditioning load (kW)

 

Indoor unit

 

 

 

Outdoor unit

 

 

 

 

 

 

 

 

 

 

 

Model

 

Capacity (kW)

Model

Capacity (kW)

 

 

 

 

Cooling

Heating

 

MMU-

 

Cooling

Heating

MMY

Cooling

Heating

 

4F

4-1

 

6.0 (16 o’clock)

5.4

 

 

AP0241H

7.1

8.0

AP2801HT8

78.5

88.0

 

 

4-2

 

5.2 (14 o’clock)

4.2

 

 

AP0181H

5.6

6.3

 

 

 

 

 

 

4-3

 

5.0 (14 o’clock)

4.2

 

 

AP0181H

5.6

6.3

 

 

 

 

 

 

4-4

 

3.2 (12 o’clock)

2.7

 

 

AP0121H

3.6

4.0

 

 

 

 

 

 

4-5

 

6.4 (10 o’clock)

5.4

 

 

AP0241H

7.1

8.0

 

 

 

 

 

3F

3-1

 

12.7

12.0

 

 

AP0481H

14.0

16.0

 

 

 

 

 

2F

2-1

 

4.8

4.5

 

 

AP0181H

5.6

6.3

 

 

 

 

 

 

2-2

 

4.6

4.8

 

 

AP0181H

5.6

6.3

 

 

 

 

 

 

2-3

 

 

 

 

 

 

 

 

1F

1-1

 

6.5

6.0

 

 

AP0241H

7.1

8.0

 

 

 

 

 

 

1-2

 

6.5

6.3

 

 

AP0241H

7.1

8.0

 

 

 

 

 

 

1-3

 

7.2

7.0

 

 

AP0301H

9.0

10.0

 

 

 

 

 

 

1-4

 

5.1

4.5

 

 

AP0181H

5.6

6.3

 

 

 

 

 

Note: ( ): Peak occurrence time

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Piping distance

 

 

 

Capacity correction

Capacity check after correction

 

 

Floor

Room No.

 

Equivalent

Height

 

Pipe correction x

 

 

Capacity (kW)

 

Result

 

 

 

 

 

length (m)

difference (m)

 

temp. correction

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Cooling

Heating

Cooling

Heating

 

 

 

 

4F

4-1

 

43

12

 

0.920

0.957

6.5

6.9

 

Good

 

 

 

4-2

 

 

 

 

x

x

5.2

5.4

 

 

 

 

 

4-3

 

 

 

 

1.0

1.0

 

5.2

5.4

 

 

 

 

 

4-4

 

 

 

 

x

x

3.3

3.5

 

 

 

 

 

4-5

 

 

 

 

1.0

0.95

6.5

6.9

 

 

 

 

3F

3-1

 

 

 

 

=

 

x

12.9

13.8

 

 

 

2F

2-1

 

 

 

 

0.920

0.95

5.2

5.4

 

 

 

 

 

2-2

 

 

 

 

 

 

=

 

5.2

5.4

 

 

 

 

 

2-3

 

 

 

 

 

 

0.864

 

 

 

 

1F

1-1

 

 

 

 

 

 

 

 

6.5

6.9

 

 

 

 

 

1-2

 

 

 

 

 

 

 

 

6.5

6.9

 

 

 

 

 

1-3

 

 

 

 

 

 

 

 

8.3

8.6

 

 

 

 

 

1-4

 

 

 

 

 

 

 

 

5.2

5.4

 

 

 

26

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Image 26
Toshiba HFC R-410A Procedure and result of equipment selection, Air conditioning load Equipment selection Floor Room No