Press 2ndF EXE to compute the statistical test. The following results will be
displayed. Press ▼to see the rest of the results.
The first item on the screen, µ1>µ2, is the alternate hypothesis of the statistical
test. Supporting the alternate hypothesis in this case would mean "da Bears,"
on the average, win more games than the Packers in a season and thus are a
better ball team. The null hypothesis is not shown on the screen because it is
always the same as the alternate except it is an equality (µ1=µ2). The second
item on the screen is the observed statistic from the sample (observed t).
From it, the third item on the screen is calculated and it represents the
decision statistic (pvalue).
In our problem, the pvalue is .0323 which is less than .05. Our decision is to
reject the null hypothesis that µ1=µ2 and support the alternate hypothesis that
µ1>µ2. This test clearly shows that "da Bears" average more wins a season than
the Packers and thus are a better football team.
The fifth and sixth values show the sample averages. On the average, "da Bears"
win approximately 9 games a season, whereas the Packers win 7. The seventh
and eighth values show the sample standard deviations are nearly the same.
Statistical Tests/STATISTICS USING THE SHARP EL-9600 53