Panasonic IMC80A specifications Example

[Reference]

Example

Command dividing

D =

∆M x E x R

... Formula (3)

D =

Pr46

x 2

Pr4A

multiplier ratio

L

Pr4B

Lead of ball screw L = 10mm

Determine

parameters Pr46,

Reduction ratio R=1

0.005 x 10000 x 1

Pr4A and Pr4B so

Pr46 = 10000

Position resolution

that D=5. Consider

1

D =

Pr4A = 0

∆M = 0.005mm

10

the following:

Pr4B = 2000

For the encoder of 2500 P/r

= 5

10000 x 2

0

(E=10000P/r)

D =

2000

Lead of ball screw L = 20mm

Reduction ratio R=1

0.0005 x 10000 x 1

D<1 is not

D = 1 is a condition

Position resolution

appropriate to

2

∆M = 0.005mm

D =

20

determination of

of minimum

resolution.

For the encoder of 2500 P/r

= 0.25

the accuracy.

(E=10000P/r)

Example

Motor rotation speed (r/min)

N = F x

D

x 60

... Formula (5)

E

Lead of ball screw L= 20mm

0.005 x 10000 x 1

... Formula (3)

D =

20

Reduction ratio R=1

= 25

Position resolution

2.5

∆M = 0.005mm

N = 500000 x

x 60 ... Formula (5)

Line driver pulse input

10000

500 kpps

= 7500

For the encoder of 2500 P/r

Thus, motor specification is not met.

Command dividing

D =

N x E

... Formula (6)

D =

Pr46

x 2

Pr4A

multiplier ratio

F x 60

Pr4B

Determine

parameters Pr46,

To make motor rotation speed

3000 x 10000

Pr4A and Pr4B so

Pr46 = 10000

D =

= 1

that D=1. Consider

Pr4A = 0

3000 r/min under the same

500000 x 60

the following:

Pr4B = 10000

condition as above, with lead of

10000 x 2 0

ball screw of L = 20 mm and the

D =

line driver pulse input of 500 kpps.

10000

Then, distance per command pulse (mm) is as follows:

(position resolution)

∆M =

D

x

1

x L =

1

x

1

x 20 = 0.002mm

E

1

R

10000

Reference

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