Allowable Moment of Inertia
Table
|
|
|
|
|
| Allowable Load Torque |
| ||||
| Robot Model |
|
|
|
|
|
|
|
|
|
|
|
|
| R2 Axis |
|
| B Axis Rotation |
|
| R1 Axis Rotation |
| |
|
|
|
|
|
|
|
|
| |||
|
|
|
| Rotation |
|
|
|
|
| ||
|
|
|
|
|
|
|
|
|
|
| |
| HX300/300L |
| 150kg·m²(15.3kgf·m·s²) |
| 30 kg·m²(3.1 kgf·m·s²) | ||||||
|
|
|
|
|
| ||||||
| HX400 |
| 120 kg·m²(12.2 kgf·m·s²) |
| 50 kg·m²(5.1 kgf·m·s²) | ||||||
|
|
|
|
|
|
|
|
|
|
| |
|
| 117.6 kg·m²(12.0 kgf·m·s²) |
| 58.8 kg·m²(6.0 | |||||||
|
|
| kgf·m·s²) | ||||||||
|
|
|
|
|
|
|
|
|
| ||
|
|
|
|
|
|
|
|
|
|
|
|
Loads must be kept below maximum conditions shown in [Fig. 3.8~Fig 3.10].
[Fig 3.8] and [Fig 3.10] show the possible range in which a point load can be positioned, assuming the attached load is a particle. However, as the actual load(End Effector) is not a particle, calculate and evaluate the moment of inertia on each axis. The following exmple shows moment of inertia calculation assuming the attached load is a particle.
[Example〕An attached load weight is 200Kg with the 【 HX300 】Model
Allowable position of the center of gravity from the center of R1 axis
①Allowable position of the center of gravity from the center of Axis R1
LR1 ≤ (Allowable Torque) / (Load Weight)
LR1 = 687 N·m / (200Kg×9.8 m/s2) = 0.35 m
②Allowable position of the center of gravity from the allowable moment of
inertia
LR1 ≤ (Allowable moment of inertia/ Load Weight)1/2
=(30 kg·m2 / 200 kg )1/2 = 0.387 m( > 0.35 m)
From the above result, the maximum distance from the center of R1 axis becomes 0.35 m, being restricted by the allowable moment of inertia.