Chapter 2 -
12522 = decrease so that motor voltage is 90 %. Flux and thus the field current as well are reduced.
How to proceed:
1.decrease 12522 (in steps of 100 at a time)
2.press ACT, read off motor voltage
3.press PAR and correct 12522 if necessary (then continue with 2.) Read out and note down value of:
11003 | = | (will later be entered in 1015) |
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12522 | = decrease so that motor voltage is 70%. | |
Flux and thus the field current as well are reduced. | ||
| Proceed as described in (1. / 2. / 3.) above! | |
Read out and note down value of: | ||
11003 | = | (will later be entered in 1014) |
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12522 | = decrease so that motor voltage is 40%. | |
Flux and thus the field current as well are reduced. | ||
| Proceed as described in (1. / 2. / 3.) above! | |
Read out and note down value of: | ||
11003 | = | (will later be entered in 1013) |
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12522 | = 4095 |
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12516 | = 0 |
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Internal reference value equal to zero.
Switch OFF power, thus stopping the drive!
1002 = 12512
1004 = 0
1009 = 10%
1010 = - 99%
1014 = equal to the 2nd value of 11003
1013 = equal to the 3rd value of 11003 Linearization function matched to field circuit.
501 = 90 % of the rated motor voltage.
1012 = 90 % of the value on the motor rating plate.
This measure serves to provide a greater safety margin for the motor voltage during
IV A 2 - 18 | DCS 500B / DCP 500B Operating Instructions |
3ADW000055R0401_DCS500B_Operating Instruction_e_d