Solution: I=0.0072_A.

Resonant Frequency (2, 17)

Equation:

ω 0 =

1

Qs =

1

C

Qp = R

C

ω 0 = 2 ⋅ π ⋅ f0

---------------LC

R---

---

---

 

 

 

L

 

L

 

Example:

Given: L=500_mH, C=8_lF, R=10_ω.

Solution: ω0=500_r / s, Qs=25.0000, Qp=0.0400, f0=79.5775_Hz.

Plate Capacitor (2, 18)

Equation:

0 ⋅∈r A C = ------------------------

d

Example:

Given: C=25_lF, r=2.26, A=1_cm^2.

Solution: d=8.0042E-9_cm.

Cylindrical Capacitor (2,19)

Equation:

2 ⋅ π ⋅0 r L C = ---------------------------------------

roLN----

ri

5-16 Equation Reference