Solution: I=0.0072_A.

Resonant Frequency (2, 17)

Equation:

ω 0 =

1

Qs =

1

C

Qp = R

C

ω 0 = 2 ⋅ π ⋅ f0

L C

 

 

R

 

L

 

L

 

Example:

Given: L=500_mH, C=8_ F, R=10_ω.

Solution: ω0=500_r / s, Qs=25.0000, Qp=0.0400, f0=79.5775_Hz.

Plate Capacitor (2, 18)

Equation:

C= 0 ⋅∈r A d

Example:

Given: C=25_ F, r=2.26, A=1_cm^2.

Solution: d=8.0042E9_cm.

Cylindrical Capacitor (2,19)

Equation:

C = 2 ⋅ π ⋅0 r L

LNro

ri

516 Equation Reference

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Image 452
HP 50g Graphing, 48gII Graphing Resonant Frequency 2, Plate Capacitor 2, Cylindrical Capacitor 2,19, Solution I=0.0072A