HP 50g Graphing, 48gII Graphing manual @·J%Eiz%

1.25 !Æ

Example: The following program, EIZ, constructs a custom menu to emulate the HP Solve application for a capacitive electrical circuit. The program uses the equation E = IZ, where E is the voltage, I is the current, and Z is the impedance.

Because the voltage, current, and impedance are complex numbers, you can’t use the HP Solve application to find solutions. The custom menu in EIZ assigns a direct solution to the leftshifted menu key for each var iable, and assigns store and recall functions to the unshifted and rightshifted keys — the actions are analogous to the HP Solve application. The custom menu is automatically stored in CST, replacing the previous custom menu — you can press

!£to restore the menu.

Program:	Comments:
«
DEG 15 SF 16 SF	Sets Degrees mode. Sets flags –15 and –16 to
2 FIX	display complex numbers in polar form. Sets
	the display mode to 2 Fix.
{	Starts the custom menu list.
{ "E" { « 'E' STO »	Builds menu key 1 for E.
« I Z * DUP 'E' STO	Unshifted action: stores the object in E. Left
"E: " SWAP + CLLCD	shift action: calculates I × Z, stores it in E, and
1 DISP 3 FREEZE »	displays it with a label. Rightshift action: recal ls
« E » } }
	the object in E.
{ "I" { « 'I' STO »	Builds menu key 2.
« E Z / DUP 'I' STO
"I:"SWAP + CLLCD
1 DISP 3 FREEZE »
« I » } }
{ "Z"{ « 'Z' STO »	Builds menu key 3.
« E I / DUP 'Z' STO
"Z:" SWAP + CLLCD
1 DISP 3 FREEZE »
« Z » } }
}	Ends the list.
MENU	Displays the custom menu.
»
`OEIZ ‰	Stores the program in EIZ.

For a 10volt power supply at phase angle 0°, you m easure a current of 0.37amp at phase angle 68°. Fi nd the impedance of the circuit using EIZ.

@·J%EIZ%

Key in the voltage value. !Ü10 ~@6 0

154 RPL Programming