Heat Capacity (6, 1)

Equations:

Q = m ⋅ c ⋅ T

Q = m ⋅ c ⋅ (Tf – Ti)

Example:

Given: ΔT=15_°C, Ti=0_°C, m=10_kg, Q=25_kJ.

Solution: Tf=15_°C, c=.1667_kJ/(kg∗K)

Thermal Expansion (6, 2)

Equations:

δ = α ⋅ L ⋅ T δ = α ⋅ L ⋅ (Tf – Ti)

Example:

Given: ΔT=15_°C, L=10_m, Tf=25_°C, δ=1_cm.

Solution: Ti=10_°C, α=6.6667E–5_1/°C.

Conduction (6, 3)

Equations:

q =

k-----------⋅ A

⋅ T

q =

k-----------⋅ A ⋅ (Th – Tc)

 

L

 

 

L

Example:

Given: Tc=25_°C, Th=75_°C, A=12.5_m^2, L=1.5_cm, k=0.12_W/ (m∗K)

Solution: q=5000_W, ΔT= 50_°C.

Equation Reference 5-29