Heat Capacity (6, 1)

Equations:

Q = m ⋅ c ⋅ ΔT

Q = m ⋅ c ⋅ (Tf – Ti)

Example:

Given: T =15_°C, Ti=0_°C, m=10_kg, Q=25_kJ.

Solution: Tf=15_°C, c=.1667_kJ/(kgK)

Thermal Expansion (6, 2)

Equations:

δ = α ⋅ L ⋅ ΔT δ = α ⋅ L ⋅ (Tf – Ti)

Example:

Given: T =15_°C, L=10_m, Tf=25_°C, δ=1_cm.

Solution: Ti=10_°C, α=6.6667E–5_1/°C.

Conduction (6, 3)

Equations:

q =

k----------- A

⋅ ΔT

q =

k----------- A ⋅ ( Th – Tc)

 

L

 

 

L

Example:

Given: Tc=25_°C, Th=75_°C, A=12.5_m^2, L=1.5_cm, k=0.12_W/ (mK)

Solution: q=5000_W, T = 50_°C.

Equation Reference 529

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HP 48gII Graphing, 50g Graphing manual Heat Capacity 6, Thermal Expansion 6, Conduction 6