Normal Stress (14, 1)
Equations:
σ = E ⋅ ∈ | δ | σ | P |
∈ = | = | ||
| L |
| A |
Example:
Given: P=40000_lbf, L=1_ft, A=3.14159265359_in^2, E=10E6_psi,
Solution: δ=0.0153_in, ∈ =0.0013, σ=12732.3954_psi.
Shear Stress (14, 2)
Equations:
τ = G ⋅ γ | γ | = | τ | = | |
|
| L |
|
| J |
Example:
Given: L=6_ft, r=2_in, J=10.4003897419_in^4, G=12000000_psi, τ=12000_psi.
Solution: T=5200.1949_ft∗lbf, φ=2.0626_°, γ
Stress on an Element (14, 3)
Stresses and strains are positive in the directions shown.
Equation Reference