HP 48gII Graphing, 50g Graphing manual Normal Stress 14, Shear Stress 14, Stress on an Element 14

Normal Stress (14, 1)

Equations:

σ = E ⋅ ∈	∈ =	δ	σ	=	P
		L			A

Example:

Given: P=40000_lbf, L=1_ft, A=3.14159265359_in^2, E=10E6_psi,

Solution: δ=0.0153_in, ∈ =0.0013, σ=12732.3954_psi.

Shear Stress (14, 2)

Equations:

τ = G ⋅ γ	γ	= r ⋅ φ	τ	=	T ⋅ r
		L			J

Example:

Given: L=6_ft, r=2_in, J=10.4003897419_in^4, G=12000000_psi, τ=12000_psi.

Solution: T=5200.1949_ft∗lbf, φ=2.0626_°, γ =5.7296E–2_°.

Stress on an Element (14, 3)

Stresses and strains are positive in the directions shown.

Equation Reference 557