Equations:
σ x1 = | + | ⋅ COS(2 ⋅ θ ) +τxy ⋅ SIN(2 ⋅ θ ) | ||
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σx1 +σ y 1 = σ x +σ y
σ x
τx1y 1 =
Example:
Given: σx=15000_kPa, σy=4755_kPa, τ xy=7500_kPa, θ=30_°.
Solution: σx1=18933.9405_kPa, σy1=821.0595_kPa, τ x1y1=
Mohr’s Circle (14, 4)
Equations:
σ 1 = | + | + ρxy2 | ||
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σ1 + σ 2 = σ x + σ y
SIN(2 ⋅ θ p1) = | τxy |
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θ p2 = θ p1 + 90 |
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θ s = θ p1 – 45 |
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Example:
Given:
Solution: σ1=