Equations:

σ x1 = σ

τx 1y 1

x + σ y + σ x – σ y COS (2 ⋅ θ ) + τxy S IN(2 ⋅ θ )

2 2

σx 1 +σ y 1 = σ x + σ y

σ x – σ y

S IN(2 ⋅ θ ) + τxy ⋅ σ y

= 2

Example:

Given: σx=15000_kPa, σy=4755_kPa, τ xy=7500_kPa, θ=30_°.

Solution: σx1=18933.9405_kPa, σy1=821.0595_kPa, τ x1y1= 686.2151_kPa.

Mohr’s Circle (14, 4)

Equations:

σ 1 =

σ-----x-----+-----σ----y--

+

σ-----x---------σ-----y-

+ ρxy2

 

2

 

2

 

σ1 + σ 2 = σ x + σ y

SIN(2 ⋅ θ p1) = -------

τxy

 

 

 

σ-----x---------σ--------y---

2-------------------

----------2----------

+ τxy

 

 

 

 

 

 

 

 

 

θ p2 = θ p1 + 90

 

 

τmax =

σ-----1---------σ-----2-

 

 

 

 

 

2

θ s = θ p1 – 45

 

 

σ avg =

σ-----x-----+-----σ----y--

 

 

 

 

 

2

Example:

 

 

 

 

 

Given: σx=5600_psi, σy=18400_psi,

τ xy=4800_psi.

Solution: σ1= 4000_psi, σ2= 20000_psi,

θp1=18.4349_°, θp2=108.4349_°, τ max=8000_psi,

θs= 26.5651_°, σavg= 12000_psi.

 

 

 

 

558 Equation Reference

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Image 494
HP 50g Graphing, 48gII Graphing manual Mohr’s Circle 14, Example