Circular Ring (11, 5)
Equations:
A = π ⋅ (ro | 2 | – ri | 2 | ) | I = | π | 4 | – ri | 4 | ) |
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J = | π | ⋅ (ro | 4 | – ri | 4 | ) | Id = I + A ⋅ d | 2 |
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Example:
Given: ro=4_∝, ri=25.0Å, d=.1_mil.
Solution:
Triangle (11, 6)
Equations:
b ⋅ h A =
2
b ⋅ h3 Ix =
36
P = b + v2 + h2 + (b – v)2 + h2
b ⋅ h ⋅ ( 2 ⋅ 2) Iy =
36
J = | + b2 | – b ⋅ v + v2) | Id = Ix + A ⋅ d2 | |
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Example:
Given: h=4.33012781892_in, v=2.5_in, P=15_in, d=2_in.
Solution: b=5.0000_in, Ix=11.2764_in^4, Iy=11.2764_in^4, J=22.5527_in^4, A=10.8253_in^2,
Id=54.5776_in^4.