Samsung S3F80JB manual Call Call Procedure, @Sp Pcl Pch

INSTRUCTION SETS3F80JB

CALL — Call Procedure

CALL	dst
Operation:	SP	←	SP – 1
	@SP	←	PCL
	SP	←	SP –1
	@SP	←	PCH
	PC	←	dst

The current contents of the program counter are pushed onto the top of the stack. The program counter value used is the address of the first instruction following the CALL instruction. The specified destination address is then loaded into the program counter and points to the first instruction of a procedure. At the end of the procedure the return instruction (RET) can be used to return to the original program flow. RET pops the top of the stack back into the program counter.

Flags: No flags are affected.

Format:

opc	dst
opc	dst
opc	dst

Bytes	Cycles	Opcode	Addr Mode
		(Hex)	dst
3	14	F6	DA
2	12	F4	IRR
2	14	D4	IA

Examples: Given: R0 = 35H, R1 = 21H, PC = 1A47H, and SP = 0002H:

CALL	3521H	→	SP = 0000H
			(Memory locations 0000H = 1AH, 0001H = 4AH, where
			4AH is the address that follows the instruction.)
CALL	@RR0 →		SP = 0000H (0000H = 1AH, 0001H = 49H)
CALL	#40H	→	SP = 0000H (0000H = 1AH, 0001H = 49H)

In the first example, if the program counter value is 1A47H and the stack pointer contains the value 0002H, the statement "CALL 3521H" pushes the current PC value onto the top of the stack. The stack pointer now points to memory location 0000H. The PC is then loaded with the value 3521H, the address of the first instruction in the program sequence to be executed.

If the contents of the program counter and stack pointer are the same as in the first example, the statement "CALL @RR0" produces the same result except that the 49H is stored in stack location 0001H (because the two-byte instruction format was used). The PC is then loaded with the value 3521H, the address of the first instruction in the program sequence to be executed. Assuming that the contents of the program counter and stack pointer are the same as in the first example, if program address 0040H contains 35H and program address 0041H contains 21H, the statement "CALL #40H" produces the same result as in the second example.

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