10-2 Matrices
8310MTRX.DOC TI-83 international English Bob Fedorisko Revised: 02/19/01 12:35 PM Printed: 02/19/01 1:36
PM Page 2 of 16
Getting Started is a fast-paced introduction. Read the chapter for details.
Find the solution of X + 2Y + 3Z = 3 and 2X + 3Y + 4Z = 3. On the TI-83, you
can solve a system of linear equations by entering the coefficients as elements
in a matrix, and then using rref( to obtain the reduced row-echelon form.
1. Press . Press ~ ~ to display the
MATRX EDIT menu. Press 1 to select 1: [A]¸
2. Press 2 Í 4 Í to define a 2×4
matrix. The rectangular cursor indicates
the current element. Ellipses (...) indicate
additional columns beyond the screen.
3. Press 1 Í to enter the first element.
The rectangular cursor moves to the
second column of the first row.
4. Press 2 Í 3 Í 3 Í to complete
the first row for X + 2Y + 3Z = 3.
5. Press 2 Í 3 Í 4 Í 3 Í to
enter the second row for 2X + 3Y + 4Z = 3.
6. Press y [QUIT] to return to the home
screen. If necessary, press ‘ to clear
the home screen. Press ~ to
display the MATRX MATH menu. Press } to
wrap to the end of the menu. Select B:rref(
to copy rref( to the home screen.
7. Press 1 to select 1: [A] from the
MATRX NAMES menu. Press ¤ Í. The
reduced row-echelon form of the matrix is
displayed and stored in Ans.
1X N 1Z = L3 so X = L3 + Z
1Y + 2Z = 3 so Y = 3 N 2Z
Getting Started: Systems of Linear Equations